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Finding General Solution of 4 SinA Sin2A Sin4A = Sin3A
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Prove that: cos³A.cos 3A + sin³A.sin 3A = cos³2A
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Sin3A...... proof.
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Sin3A...... proof.
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`sin3A+sin2A-sinA = 4sinA*cos(A/2)*cos((3A)/(2))`
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If `sin3A=cos(A-26^)` , where 3A is an acute angle, find the value of A....
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