
SOLUTION: what does y=mx+b mean? - Algebra Homework Help
The value of b is the y-intercept, which is the point where the graph crosses the y-axis. The number m is the slope of the line, where slope m = rise over run. It gives the steepness of the line. And of course, x and y are variables which change within the graph from one point to another.
SOLUTION: how do you find the b in y=mx+b - Algebra …
the standard form of y = mx + b becomes y = 2x + b now you take the point (x,y) = (3,5) that is on the line (has to be on the line) and replace x and y in the equation with it. the equation becomes 5 = 2*3 + b then you solve for b. in this case b = 5-1 = -1 your equation becomes y = 2x - 1 graph of that equation looks like:
SOLUTION: what do the variables in the equation y=mx+b mean?
Question 206373: what do the variables in the equation y=mx+b mean? Answer by ... b=y int y=variable on ...
my understanding is that m is the slope and b in the y intercept
The x and y are coordinates of a point on a rectangular coordinate system. So let's say m=2 and b=1 Then at x=1 y=mx+b=2*1+b=3 Then at x=0 y=2*0+1=1. Using these two points you can plot a line as shown below and note the slope of 2 (one unit to the right means two units up) and y-intercept=b=1 at x=0 or at point (0,1):
SOLUTION: If a line has an x-intercept at x=-3 and a y-intercept at …
Question 1205693: If a line has an x-intercept at x=-3 and a y-intercept at y=2 find its equation in the form y=mx+b Answer by MathLover1(20819) ( Show Source ): You can put this solution on YOUR website!
SOLUTION: Give the domain and range. Y=mx+b, where m and b …
Y=mx+b, where m and b are real numbers and are not equal to zero. D: R: Answer by solver91311(24713 ...
SOLUTION: Suppose that the line with equation y=mx+b passes …
Suppose that the line with equation y=mx+b passes through the points (4,5) and (3,-1) Then m+b=?. m is just the slope between the two points: m = (y2-y1)/(x2-x1) m = (-1-5)/(3-4) m = -6/-1 m = 6. to find b, plug one point (4,5) and the slope into equation: y=mx+b 5=6(4)+b 5=24+b-19 = b. So, m+b = 6-19 = -13
2. Write an equation of the line containing the given point and ...
Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y = mx + b (4,5); 3x + y = 4 The equation of the line is y = What? 2. Write an equation of the line containing the given point and perpendicular to the given line. (3, - 3); 8x +7y = The equation of the line is y = What?
SOLUTION: y=mx+b I am having a having a problem figuring out …
The slope-intercept form is: y = mx + b. m = slope m = rise over the run m = change in y / change in x m = 0 if the line is horizontal m = undefined if the line is vertical b = y-intercept y-intercept is the point (0, b). In your given equation: y = 4 y = (3/5)*x + b so 4 = (3/5)*x + b m = 3/5 This means that y changes 3 units when x changes 5 ...
SOLUTION: Convert the equation 2x - 4y =8 in the form y = mx + b.
-4y/(-4) = (8 - 2x)/(-4) (LHS becomes 'one' times y, which is written simply as 'y') y = -2x/(-4) + 8/(-4) This is in the form y = mx + b m is the slope (rise / run) and here it is 1/2 b is the y-intercept, it is where the line meets the y-axis and is-2 in this case. Note that the y-axis is where x=0, so if you set x=0 in y=mx+b you get y=b.