Mar 16, 2015 · In that circuit diagram, the Potential Difference between the V+ and V- connections is equal to the 'Battery Voltage'. Those two resistors, being equal, will ensure that the PD between the terminals and the one marked VGND will be +V battery /2 and -V battery /2 (Whatever you connect that VGND terminal to it will be half way between the two ...

Jan 16, 2010 · Homework Statement Suppose V is a vector space over F. Prove that 0v(vector) = 0(vector) for an arbitrary vector v belong to V Homework Equations... Insights Blog -- Browse All Articles -- Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio/Chem ...

Oct 27, 2012 · You could measure V=0 and I=0 off a glass cup. :P If you are talking about circuit theory: then V=0 is a short circuit AND there can be current flowing through it I=0 is an open circuit AND there can be a voltage across the two non-connected wires. But those ONLY count when your circuit is ON in some way. What are you trying to do?

Dec 28, 2012 · As an example, consider the operator T in R^2 that is a counter clockwise rotation of 90 degrees around the origin. Thus , T(x,y) = (-y,x). Obviously, Tv is orthogonal to v for every v in R^2, even though T is not 0. Proposition : if V is a complex inner product space and T is an inner product space on V such that <Tv,v>=0 for all v in V, then ...

Jan 26, 2013 · A falling object satisfies the initial value problem: dv/dt = 9.8 - v/5, v(0) = 0 1.Find the time that must elapse for the object to reach 98% of its limiting velocity. answer: t = 19.56, and for completeness, v = -49e-t/5 + 49 2.How far does the object fall in the time found in part a...

Oct 30, 2005 · Hi can anyone explain the logistics of vf^2 = vi^2 + 2ad to me? i mean its one thing to simply remember the equation but, to understand how they came about it is way more helpful. thx a lot :biggrin:

Aug 3, 2011 · V = e^(-k/m t + C) = Vo e^(-k/m t) (BTW. e^0 = 1) Now you have a special solution to the equation (1), and a general solution to the homogeneous equation. The general solution to (1) is the sum of above V = mg/k + Vo e^(-k/m t) Vo may be found remembering that the initial velocity was zero. 0 = mg/k + Vo e^0 Vo = -mg/k

Feb 7, 2006 · Right, that's basically it. Since div(v)=0 the flux through any closed surface is zero. The flux is a measure of how much fluid flows through the surface. Since the surface is closed there is no net accumulation of fluid in the volume.

Oct 5, 2007 · In a ballistic pendulum an object of mass m is fired with an initial speed v_0 at a pendulum bob. The bob has a mass M, which is suspended by a rod of length L and negligible mass. After the collision, the pendulum and object stick together and swing to a maximum angular displacement (theta) as shown

Nov 23, 2013 · Well I was going through class lecture notes and my professor wrote this When x = A(the maximum value), v=0: E=1/2kA^2 When v = wA, x=0: E=1/2mw^2A^2 where w = omega, A = amplitude, k = spring constant, m = mass, v = velocity and apparently both equations are equal, i would like to...