2017年2月7日 · 6sin^3 (10)-6sin10+1=0 give sin10 value but we have don't ideas factorize about this equation. we only find sin10 approx by calculus concept of maxima and minima but this is advance math .you will study conceptually in class 12th

2015年11月4日 · Hi , LHS = ( Cos 10 + Sin 10 ) / ( Cos 10 - Sin 10 ) { Multiply numerator and and denominator with 1 / Cos 10 }

2017年6月11日 · Sin10+sin20+sin40+sin50=sin70+sin80 Get the answers you need, now! PranshuNidhi PranshuNidhi 12.06.2017 ...

2018年9月14日 · Sin10° + sin 50° - sin 80° + sin 140°=√2. Sin 25° - 5677966

2023年7月1日 · 8. We know that sin100° = sin(90° + 10°) = sin10° because the sine function has a periodicity of 360°. Therefore, our expression simplifies to: 2cos10° + sin10° - sin40° + sin80° 9. Now, let's consider the values of sin10°, sin40°, and sin80°. These angles fall within the first quadrant, where the sine function is positive.

2016年10月24日 · Answer. soln. 1/sin10 - √3cos10 => cos10- √3sin10 / Sin10 cos10 {take LCM} => 2[ cos10- √3 sin10 / 2sin10cos10 } {multiply and divide 2 to nr n dr}

2019年7月27日 · A trigonometric equation 2sin θ = √3cos10 + sin10. To Find, The value of this θ. Solution, The given expression is . 2sin θ = √3cos10 + sin10. sin θ = √3/2cos10 + 1/2sin10. Now, we know that. sin 60 = √3/2. cos 60 = 1/2. Now, substituting the values. sin θ = sin60*cos10+cos60*sin10. sin θ = sin (60+10) ( sin(a+b) = sina*cosb ...

2017年9月14日 · Given, A trigonometric equation sin70°cos10°-cos70°sin10°=√3/2. To Prove, The value of sin70°cos10°-cos70°sin10°=√3/2.

2018年12月4日 · Sin10° =1/2 - 6960672. ankushkumar539 ankushkumar539 05.12.2018 Math Secondary School ...

2017年12月2日 · Prove that : sin10°sin50°sin70°=1/8 - 1904582