In the case of the $\ce{N2 + O2 -> 2NO}$ , $\Delta H$ and $\Delta S$ are both positive, so the reaction is thermodynamically favorable at high temperature (such as in lightning) but not at low temperature. If the temperature drops to room temperature after NO is formed, it is thermodynamically favorable for NO to decompose to nitrogen and oxygen.

2020年6月16日 · $$\ce{N2 + O2 -> 2NO}$$ So I know the second reaction is endothermic as we need to break triple bonds between nitrogen molecules. I am not sure about the first one. Actually, I want to know if there is some way we can decide whether a reaction is endothermic or exothermic just by looking at the equation?

2019年4月22日 · N2+O2=N2O balance this equation - 9473902. 2N2 + O2 - - - - - - - > 2N2O. Is the balanced equation . Hope it helps you

2024年3月26日 · The molecular orbital configurations of O2+ and N2- can be determined using molecular orbital theory. Starting with O2+, which is the molecular ion of oxygen with a positive charge, we can write the electron configuration by adding one electron to the molecular orbital diagram of O2. The molecular orbital diagram of O2 looks like this:

2019年7月22日 · I think that it should be F2 because F is smaller than N and O thus having a small bond length. And small bond length means greater energy (my teacher told me). But the answer is N2.

2023年5月31日 · N2 + O2 → N2O5 Explanation: We can see that there are equal numbers of nitrogen (N) atoms on both sides, so we don't need to adjust the number of N atoms. However, we can balance the equation by adjusting the number of oxygen atoms on each side. On the left-hand side, we have 2 oxygen atoms from O2.

2017年4月29日 · So $\ce{N2}$ (or $\ce{O2}$) only has a single vibrational mode $(3 × 2 - 5 = 1),$ no permanent dipole, and can only have a weak induced dipole, so it's absorption in the IR is very small. $\ce{CO}$ also has only a single vibrational mode, but there is a permanent dipole moment and therefore the molecule has the ability to absorb in the IR ...

2024年4月17日 · What I did is, I went to the HITRAN database and downloaded the line strengths of both $\ce{N2}$ and $\ce{O2}$, and I extracted the $\texttt{.par}$ file, and I am able to see some obvious peaks. I also have a range of interest for both temperature (~70-300 K) and pressure (~300-3000 Pa), but I don't know where to start.

2015年8月8日 · The question in fact does not make a lot of sense since $\ce{N2-}$ is known to be electronically unstable, i.e. its energetically less favourable then the system of $\ce{N2}$ plus a free electron. There exist few metastable resonance states of $\ce{N2-}$ that correspond to attachment of the scattered electron to excited valence states 1 , but ...

2017年5月11日 · Click here 👆 to get an answer to your question ️ Calculate the bond order of N2,O2,O2^+and O2^- aaakings1245 aaakings1245 11.05.2017