2013年7月31日 · The expression set >>= 1; means set = set >> 1; that is right shift bits of set by 1 (self assigned form of >> bitwise right shift operator check Bitwise Shift Operators).

@EugeneSh.: strictly, there is no longer a =+ operator in C. It ceased to be a part of C in the mid-70s. Note that =+, =-, =& can both appear in modern C — even =* if the term following is a pointer. Most of the others can't. However, the meaning is of the two separate operators; the fact that they're touching is immaterial. –

2011年3月30日 · The * in declaration means that the variable is a pointer to some other variable / constant. meaning it can hold the address of variable of the type. for example: char *c; means that c can hold the address to some char, while int *b means b can hold the address of some int, the type of the reference is important, since in pointers arithmetic ...

2018年4月3日 · In early C, the operator && did not exist, and because of that & was used for this purpose. One way to explain it is that you could imagine that & is the same thing as applying && on each individual bit in the operands. Also note that & has lower precedence than &&, even though intuition says that it should be the other way around.

2011年3月17日 · :: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()

2024年12月11日 · I have been looking everywhere to figure out what these mean and how they are used +=, -=, *=, /=, the most I have found is that they are, "Assignment by Addition", "Assignment by Difference", "

2016年9月11日 · Question: what is %[^\n] mean in C? Basically the \n command prints the output in the next line, but in case of C gives the Null data followed by the above problem only. Because of that to remove the unwanted data or null data, need to add Complement/negotiated symbol[^\n]. It gives all characters until the next line and keeps the data in the ...

2021年1月2日 · I have the following line of code: contents[pos++] ^= key[shift++]; What does operator ^= mean?

2009年2月21日 · It means that this function has scope only in this file. So a.c and b.c can have different foo()s, and foo is not exposed to shared objects. So if you defined foo in a.c you couldn't access it from b.c or from any other places. In most C libraries all "private" functions are static and most "public" are not.

@Shahbaz That may be the case for a java programmer, a C/C++ programmer will understand a.b.c.d and a->b->c->d as two very different things: The first is a single memory access to a nested sub-object (there is only a single memory object in this case), the second is three memory accesses, chasing pointers through four likely distinct objects ...