Multiply both sides of the equation by \left(j+3\right)\left(j+10\right), the least common multiple of j+10,j+3. j^{2}-5j-24=\left(j+10\right)\left(j-1\right) Use the distributive property to multiply j+3 by …

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2j^{2}-j-10=2\times \frac{2j-5}{2}\left(j+2\right) Subtract \frac{5}{2} from j by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

j=\frac{-3±\sqrt{3^{2}-4\left(-10\right)}}{2} All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two …

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