
What does $QAQ^{-1}$ actually mean? - Mathematics Stack …
2020年4月28日 · Let me provide some context. I was specifically looking at the application of linear algebra to the stress tensor $\sigma$ and how we get the transformed stress state in some rotated coordinate system by the following multiplication: $\sigma'=Q\sigma Q^{-1}(Q$ is a rotation matrix defined by the angle we want to rotate the axes).
abstract algebra - Prove that 1+1=2 - Mathematics Stack Exchange
2013年1月15日 · The main reason that it takes so long to get to $1+1=2$ is that Principia Mathematica starts from almost nothing, and works its way up in very tiny, incremental steps. The work of G. Peano shows that it's not hard to produce a useful set of axioms that can prove 1+1=2 much more easily than Whitehead and Russell do.
Why is $1^{\\infty}$ considered to be an indeterminate form
The indeterminate forms are often abbreviated with stuff like "$1^\infty$" but that's not what they mean. This "$1^\infty$" (in regards to indeterminate forms) actually means: when there is an expression that approaches 1 and then it is raised to the power of an expression that approaches infinity we can't determine what happens in that form.
Formula for $1^2+2^2+3^2+...+n^2$ - Mathematics Stack …
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Why is $1/i$ equal to $-i$? - Mathematics Stack Exchange
2015年5月11日 · There are multiple ways of writing out a given complex number, or a number in general. Usually we reduce things to the "simplest" terms for display -- saying $0$ is a lot cleaner than saying $1-1$ for example.
Proof that $(AA^{-1}=I) \\Rightarrow (AA^{-1} = A^{-1}A)$
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General term formula of series 1/1 + 1/2 + 1/3 ... +1/n
$$\ln(n+1)\le\sum_{i=1}^n\frac1i\le\ln(n)+1$$ This is a rather tight upper limit and lower limit you can use to approximate your answer. One could also note that $$\sum_{i=1}^n\frac1i=\int_0^1\sum_{i=0}^{n-1}x^i\ dx=\int_0^1\frac{1-x^n}{1-x}\ dx$$ We also have the Euler-Maclaurin expansion:
sequences and series - Why does this pattern work: $1 \cdot{1}
well, for 1^2 it isn't very hard to figure out, but here is the basic explanation. there is one of 11, 111, 1111, etc. in each place value until there have been as many place values as there are digits of the original number (1,111; 11,110; 111,100; and 1,111,000 for example). the amount of digits in the product is equal to (nx2)-1, where n is the original number. then, it is like a bell curve ...
Double induction example: $ 1 + q + q^2 - Mathematics Stack …
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what is 1 - 1/2 + 1/3 - 1/4 + 1/5 - 1/6 + 1/7 - 1/8 +1/9
2019年11月28日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.