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Sep 21, 2020 · Write $\cos(5x)$ as a function of $\cos(x)$, answer with a polynomial. $$e^{i\cdot5x} = \cos(5x) + i\sin(5x)$$ $$\cos(5x) + i\sin(5x) = (\cos(x) + i\sin(x))^5$$ and using the binomial theorem I th...

\int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx \sum_{n=0}^{\infty}\frac{3}{2^n} Show More

Begin by entering your mathematical expression into the above input field, or scanning it with your camera. Once you've entered the function and selected the operation, click the 'Go' button to generate the result. The calculator will instantly provide the solution to your trigonometry problem, saving you time and effort.

AI explanations are generated using OpenAI technology. AI generated content may present inaccurate or offensive content that does not represent Symbolab's view. Trig simplification can be a little tricky. You are given a statement and must simplify it to its simplest form....

5x + sinx + C Explanation: Split into two integrals; \displaystyle\int_ {_} {5} {\left. {d} {x}\right.} + \displaystyle\int_ {_} {\cos { {\left ( {x}\right)}}} {\left. {d} {x}\right.} Solve seperately; ... It is the amplitude, it will make the upper & lower bounds of the function on the y-axis higher and lower.

Divide each term in 5x = π 2 5 x = π 2 by 5 5 and simplify. Tap for more steps... The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π 2 π to find the solution in the fourth quadrant. 5x = 2π − π 2 5 x = 2 π - π 2. Solve for x x. Tap for more steps...

Use the form acos(bx−c)+ d a cos (b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. Find the amplitude |a| | a |. Find the period of cos(5x) cos (5 x). Tap for more steps... Find the phase shift using the formula c b c b. Tap for more steps... List the properties of the trigonometric function.

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Feb 1, 2017 · I was asked to find a formula for $\cos(5x)$ in terms of $\sin(x)$ and $\cos(x)$. I tried to use the formula $\cos(5x) + i\sin(5x) = (\cos(x)+i\sin(x))^5 $ and what I get is $16i\sin^5(x) - 2...