A base class pointer (CBase*) can point to an object of a type derived from CBase (like CChild). That's not what you've done, though: your base class pointer points to a base class object. That's not what you've done, though: your base class pointer points to a base class object.

2011年3月16日 · If I understand correctly you want to make ibase a virtual base class of iderived and cbase. This was there is only one instance of each of your interface classes in the class hierarchy and when you join cbase and iderived together at the cderived level the non-virtual override of MyMethodA in cbase is used because it is the dominating override.

2016年12月8日 · After using C# for the past decade or two, my C++ has gone a little rusty. If I have the following: class CBase { public: CBase(LPCTSTR pszArg1, LPCTSTR pszArg2, LPCTSTR pszArg3); virtual ~

2020年8月6日 · In the following code I return a derived class CDerived by-value from a function returning its base class, CBase. For example purposes, CDerived contains a _number field, and I understand that this is "sliced" off during its conversion to the by-value return type, CBase .

2016年6月6日 · In this case, we're converting a pointer to member of CDerived of type void() to a poitner to member of CBase ov type void(). CBase is a base of the class containing the original member, so the resulting pointer points to the original member. From [expr.mptr.oper]: Abbreviating pm-expression.*cast-expression as E1.*E2, E1 is called the object ...

2011年11月21日 · In this case - for sure it will be CBase::f(), so there's no need from access to the virtual table. And second, you need explicit call to the function, because if the call is from the constructor, f is "resolved" at compile time as it's for sure, that the called f function will be CBase::f(). So, again - there's no need from access to the ...

2014年6月9日 · To return a reference, it must be a reference to a particular object. A cDerived*& must refer to an actual cDerived* (i.e. it must be an lvalue).

2010年11月30日 · Assuming you remember to make do1() virtual you could check &ABase::do1, &BBase::do1 and &CBase::do1 at runtime. I am not convinced that comparing &ABase::do1 and &CBase::do1 will return the same value just because CBase has not overridden the function, and whether just because it does on one system means it always will.

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2012年12月22日 · class Base { public: virtual void foo() {} }; class Derived: public Base { public: virtual void foo() {} }; int main() { Base *pBase = NULL; Base objBase; Derived