Jun 25, 2016 · =sinx(1/sinx - sinx) =sinx((1 - sin^2x)/sinx) =cancel(sinx)(1 - sin^2x)/cancel(sinx) =cos^2x

"The fundamental trigonometric identities" are the basic identities: •The reciprocal identities •The pythagorean identities

Mar 7, 2018 · color(green)(=> 1 sin x * csc x = sin x * (1 / sin x) using fundamental identities. cancel( sin x )* (1 / cancel (sin x) ) = 1

Jun 7, 2018 · How do you prove #csc x - sin x = cos x cot x#? Trigonometry Trigonometric Identities and Equations Proving Identities. 2 Answers

Feb 20, 2018 · 1 csc(theta) is the reciprocal of sin(theta), meaning that csc(theta)=1/sin(theta) sin(theta) * 1/sin(theta) = sin(theta)/sin(theta)=cancel(sin(theta))/cancel(sin ...

May 18, 2016 · How do you simplify #csc θ sin θ#? Trigonometry Trigonometric Identities and Equations Fundamental ...

The best videos and questions to learn about Proving Identities. Get smarter on Socratic.

Apr 16, 2017 · yes, 1/sin^2x=csc^2x We know that sinx=1/cscx and we also know that sinxsinx=1/cscx1/cscx and so we can say sin^2x=1/csc^2x and also 1/sin^2x=csc^2x

Sep 30, 2016 · Since #cot theta=cos theta/sin theta and csc theta =1/sin theta#, the expression becomes: #(cos theta/sin theta)/(1/sintheta-sin theta)#

Mar 27, 2018 · If #csc theta=4/3#, what is the sin, cos, tan, sec, and cot?