Mar 16, 2017 · See the entire simplification process below: First, remove the negative exponent by using this rule for exponents: x^color(red)(a) = 1/x^color(red)(-a) (ab)^color(red)(-2) = 1/(ab)^color(red)(- -2) = 1/(ab)^2 This may be enough simplification depending on what has been requested. However, if you want to remove the terms from parenthesis you can use these two …

Sep 16, 2015 · It is sqrt(a*b^2)=abs(b)*sqrta. 8970 views around the world You can reuse this answer

Dec 26, 2016 · a^2b^6 In simplifying the given expression, Law of addition of exponents would apply. The exponent of both 'a' is one, hence on multiplication exponents would add to become 2. Likewise the exponents of 'b' would add to become 6. Thus the final result would be a^2b^6.

Jun 19, 2018 · logA+2logB Using the product property, we have log(AB^2) = logA+logB^2 The power is moved in the front: logB^2=2logB :. log(AB^2) = logA+2logB

Oct 1, 2017 · (a+b)/2 color(red)(>=) sqrt(ab)" " as shown below Note that: (a-b)^2 >= 0" " for any real values of a, b. Multiplying out, this becomes: a^2-2ab+b^2 >= 0 Add 4ab to both sides to get: a^2+2ab+b^2 >= 4ab Factor the left hand side to get: (a+b)^2 >= 4ab Since a, b >= 0 we can take the principal square root of both sides to find: a+b >= 2sqrt(ab) Divide both sides by 2 to get: …

Sep 2, 2017 · If a group G is Abelian, then for any two elements a and b, a*b = b*a Now, Define c=a*b which is also a member of G on virtue of closure property. Then c^2 = c*c implies (a*b)^2=(a*b)*(a*b) By associative axiom, (a*b)^2 = a*(b*a)*b But, by property of commutativity (for an Abelian group), implies (a*b)^2=a*(a*b)*b implies (a*b)^2=(a*a)*(b*b) Thus we get our …

Dec 25, 2014 · We can use the rule about division of rational expressions where you can change the division in a multiplication by flipping the second fraction.

Feb 3, 2015 · The answer is: (a+b)^3=a^3+3a^2b+3ab^2+b^3. It's easy to prove: (a+b)^3= =(a+b)(a+b)(a+b)= =(a^2+ab+ab+b^2)(a+b)= =(a^2+2ab+b^2)(a+b)= =a^3+a^2b+2a^2b+2ab^2+ab^2+b^3 ...

Mar 30, 2018 · The value of ab is 1. We can expand (a- b)^2 to see that (a- b)^2 = a^2 - 2ab + b^2, thus a^2 + b^2 - 2ab = 2. It follows that a^2 + b^2 = 2 + 2ab, and since we're given that a^2+ b^2 = 4, we can say 4 = 2 + 2ab. Doing a little algebra we get 4 = 2(1 + ab) 2 = 1 + ab ab = 1 Hopefully this helps!

Nov 16, 2015 · It is a^2+2a+ab+2b=a*(a+b)+2*(a+b)=(a+2)*(a+b) How do you find the two numbers by using the factoring method, if one number is seven more than...