
What is the antiderivative of 9/x^3? - Socratic
Jul 7, 2016 · int 9/x^3 d x=-9/(2x^2)+C int 9/x^3 d x int 9/x^3 d x=9 int (d x)/x^3 int 9/x^3 d x=9 int x^(-3) d x "now use power rule" int 9/x^3 d x=9 [1/(-3+1)x^(-3+1)] int 9/x^3 ...
How do you solve |x - 3| < 9? - Socratic
Apr 2, 2017 · See the entire solution process below: The absolute value function takes any negative or positive term and transforms it to its positive form. Therefore, we must solve the …
What is the square root of 9x^3? - Socratic
Sep 25, 2015 · =color(blue)(3xsqrtx sqrt(9x^3) can be written as: sqrt(3^2 *color(blue)(x^2*x) =color(blue)(3 *x) sqrt x =color(blue)(3xsqrtx
How do you simplify (x-3)^3? - Socratic
May 5, 2017 · How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4
How do you solve #3(2x-1)=9(x+3)#? - Socratic
Jun 18, 2018 · x = -10 Step 1, distribute the 3 and 9 into the parentheses: 3(2x-1) -> 6x-3 9(x+3) -> 9x+27 Step 2 ...
Is f(x)=(x^2-9)/(x-3) continuous at x=3? - Socratic
Dec 7, 2016 · Thus, f(x) is not continuous at x=3. Bonus: Here's a tip to determine where some functions will be discontinuous. Any x-value that makes any denominator in the function equal …
How do you integrate int (x+5)/sqrt (9-(x-3)^2) dx? - Socratic
Aug 4, 2016 · 8sin^(-1)((x-3)/3) - sqrt(9-(x-3)^2) + C I hope you like substitutions, because we're about to do a lot of them. To start, let u = x-3 implies du = dx Integral becomes: int …
How do you factor 9x^3-x? - Socratic
Jan 25, 2017 · x ( 3x + 1 )( 3x-1 ) x is common to both terms, so you can take it out of both and put the other factor in a bracket. 9x^3 -x =x ( 9x^2 - 1). (x^2 -1) and similar expressions are …
How do you find the Limit of #sqrt(x^2 - 9) / (x - 3) # as x
Sep 25, 2016 · (I am assuming that we want to stay in the real numbers.) As xrarr3^-, the numerator is approaching 6 and the denominator is a positive number approaching 0. As …
How do you solve y=4x-9 and y=x-3 using substitution? - Socratic
Mar 24, 2017 · Labelling the equations. #color(red)(y)=4x-9to(1)# #color(red)(y)=x-3to(2)# Since both equations have y as the subject we can equate the right sides.