
Resolver la Ecuación 9x-3=3 - Respuesta | Solucionador de
\[9x-3=3\] +. > < ...
How do you evaluate log_9 x=3/2? - Socratic
2016年10月27日 · x=27 Remember that in general log_b a = c means b^c=a (You really need to memorize this; it's a basic definition.)
How do you solve y=4x-9 and y=x-3 using substitution? - Socratic
2017年3月24日 · Labelling the equations. #color(red)(y)=4x-9to(1)# #color(red)(y)=x-3to(2)# Since both equations have y as the subject we can equate the right sides.
How do you solve |x - 3| < 9? - Socratic
2017年4月2日 · See the entire solution process below: The absolute value function takes any negative or positive term and transforms it to its positive form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent. -9 < x - 3 < 9 Add color(red)(3) to each segment of the system of inequalities to solve for x while keeping the …
Solve the Equation 4x-3=9 - Answer | Math Problem Solver - Cymath
Solve the Equation 4x-3=9 - Answer | Math Problem Solver - Cymath ... \\"Get
How do you prove that (x^3+9)/(x^3+8) = 1+1/(x^3+8) where x …
2018年3月14日 · Ok (x^3+9)/(x^3+8)=1+1/(x^3+8) You take away from both sides 1/(x^3+8) (x^3+9)/(x^3+8)-1/(x^3+8)=1 Since the denominator is the same you can sum the numerators (x^3+9-1)/(x^3+8)=1 (x^3+8)/(x^3+8)=1 Which is of course true as you can see
Is f(x)=(x^2-9)/(x-3) continuous at x=3? - Socratic
2016年12月7日 · Thus, f(x) is not continuous at x=3. Bonus: Here's a tip to determine where some functions will be discontinuous. Any x-value that makes any denominator in the function equal to 0 is a point of discontinuity. So for the function above, x-3=0 when x=3, and so the function will be discontinuous at x=3.
How do you solve 2x+3=9? - Socratic
2018年5月2日 · x = 3 2x + 3 = 9 We want to find the variable x, so we have to make it alone. To do so, first subtract ...
How do you find the limit lim_(xto0)(sqrt(9+x)-3)/x? | Socratic
2017年8月16日 · Begin by evaluating the expression at x=0 (sqrt(9+0)-3)/(0) = 0/0. The indeterminate form indicates that ...
How do you FOIL #(x+3)(x+3)(x+3)#? - Socratic
2015年6月16日 · FOIL will only get you part of the way, since once you multiply one pair of binomials you will have the product of a binomial and a trinomial, but (x+3)(x+3)(x+3) = x^3+9x^2+27x+27 Using FOIL, first multiply (x+3)(x+3) First: x * x = x^2 Outside: x * 3 = 3x Inside: 3 * x = 3x Last: 3 * 3 = 9 Add them together: F + O + I + L = x^2+3x+3x+9 = x^2+6x+9 To …