
SOLUTION: Solve 9^x=27 - Algebra Homework Help
SOLUTION: Solve 9^x=27 Algebra -> Exponential-and-logarithmic-functions -> SOLUTION: Solve 9^x=27 Log On Algebra: Exponent and logarithm as functions of power Section
How do you solve 9x = 27? - Socratic
Jun 15, 2016 · #9x=27# Divide both sides by #color(red)9#. #implies (9x)/color(red)9=27/color(red)9# #implies (9x)/color(red)9=(9*3)/color(red)9#
SOLUTION: what is 4/9 X 27? I don't agree with my …
Algebra -> Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: what is 4/9 X 27? I don't agree with my Grandson's answer of 12. I don't agree with my Grandson's answer of 12. …
SOLUTION: pls help...if 9^x=27^y and 8^y=16^z ... - Algebra …
Question 262500: pls help...if 9^x=27^y and 8^y=16^z, then what is the value of x:y:z?? thank u in advance Answer by Edwin McCravy(19989) ( Show Source ): You can put this solution on …
How do you solve 9x-9y=-27 and 5x+27=y using substitution
Feb 9, 2017 · See the entire solution process below: Explanation: Step 1) Because the second equation is already solved for #y#, substitute #5x + 27# for #y# in the first equation and solve …
How do you solve #9^ { x } = 27^ { x - 2} - Socratic
Jun 11, 2017 · x=6 "change the "color(blue)"base "" from " 9 to 3 rArr(3^2)^x=(3^3)^(x-2) rArr3^(2x)=3^(3x-6) "since the ...
How do you factor x^9 - 27? | Socratic
Nov 16, 2015 · You can use the difference of cubes identity to help factor this, but to find all the factors with Real coefficients requires a little more... You can partially factor x^9-27 by first …
How do I find log_27 9? - Socratic
Mar 15, 2015 · It is the solution to #27^x=9#. #27^x=9# Because #27=3^3# and #9=3^2#, we must want #(3^3)^x=3^2# But #(3^3)^x=3^(3x)#, so we also want: #3^(3x)=3^2#. Now, it is a …
SOLUTION: SOLVE FOR THE VAULE OF X: 27^X=9^X+2 - Algebra …
27^x = 9^(x+2) becomes 27^4 = 9^6 which becomes 531441 = 531441 this confirms the solution is good. ...
SOLUTION: 9^x=(1/27)^x+2 Please solve for x - Algebra …
Now we solve for x. Adding 3x to each side we get: 5x = -6 Dividing by 5 we get: If we are clever enough to see that 9 is a power of 1/27 (and vice versa) then the solution is a little faster …