13,9,5,11,6,3,3,3,3,9,9,9,5,5 Draw the histogram for these data using an initial class boundary of , an ending class boundary of , and classes of equal width. Note that you can add or remove classes from the figure. Label each class with its endpoints. …

The longhand form would be 9*9*9*9*9 basically five copies of "9" multiplied together. This is a bit tedious so it's better to write it in exponential form 9^5 which is the same thing, just much more compact. In any event, use a calculator to find that 9^5 = 9*9*9*9*9 = 59,049 So there are 59,049 different combinations.

3 + 6 + 9 = 9 + 9 = 18. the formula works. same thing happens with the larger numbers only it's much harder to show you because there's so many more numbers to add up.

) A coffee company claims that their coffee can contains 300g of coffee. Suppose the sample of 36 coffee cans provide a sample mean of = sh 292.