2015年11月1日 · x=+-8 [1]" "x^2=64 Subtract 64 from both sides. [2]" "x^2-64=64-64 [3]" "x^2-64=0 Factor out the quadratic equation. This is a special product (difference of two ...

2016年10月16日 · I got x=6 We can write it as: 2^x=2^6 so that x=6. #2^x=64# Just in case your teacher wants you to solve this the fancy way...

2018年6月19日 · Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than...

2018年1月18日 · Therefore, if we were to draw a right triangle we would find the hypotenuse to be #sqrt(x^2 + 8^2) = sqrt(x^2 + 64)#. Thus, #sectheta = sqrt(x^2 + 64)/8# , #csctheta = sqrt(x^2+ 64)/x# and #cottheta = 8/x# .

2016年7月2日 · The expression is a quadratic trinomial which is a product of two brackets.. #(x +- ?)(x +-?)# In #x^2 color(blue)- 16x color(red)+64#

2016年5月28日 · It is 64x^2-49=(8x)^2-7^2=(8x-7)*(8x+7) Algebra Polynomials and Factoring Factor Polynomials Using Special Products

2015年9月30日 · sqrt(64-x^2)=sqrt((8+x)(8-x)) sqrt(64x^2)=8x Applying the rule for difference of 2 squares, we may write this as sqrt(64-x^2)=sqrt((8+x)(8-x)) If the original question had to be sqrt(64x^2) then by laws of surds this would be equal to sqrt64*sqrt(x^2)=8x

2015年6月7日 · x^2-64=0 x^2 = 64 x=+-8. Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics

You can put this solution on YOUR website! Your domain is correct range is (0,8) when x = 8 or -8, you get f(x) = sqrt(64 - 64) = sqrt(0) = 0

2015年4月15日 · If you write #x^6-64 = (x^2)^3 - 4^3# you can factor it into: #(x+2)(x-2)(x^4 +4x^2+16)# If you write: #x^6-64 = (x^3)^2 - 8^2#, then you factor as #(x^3+8)(x^3-8)# which can be further factored as: #(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)# The second answer is factored into irreducibles (over #RR#).