
How do you factor x^6 - 1? - Socratic
2015年7月2日 · x^6-1 = (x^3-1)(x^3+1) =(x-1)(x^2+x+1)(x+1)(x^2-x+1) Use difference of squares, difference of cubes and sum of cubes: [1]: a^2-b^2 = (a-b)(a+b) [2]: a^3-b^3 = (a-b)(a ...
How do you solve 6( x - 1) =18x? - Socratic
2016年8月8日 · x=-1/2 6(x-1)=18x or x-1=(18x)/6 or x-1=3x or 3x-x=-1 or 2x=-1 or x=-1/2. Algebra Properties of Real Numbers When to Use the Distributive Property
How do you simplify #15 + 6(x + 1)#? - Socratic
3(2x + 7) 15 + 6(x+1) can be expanded as 15 + 6x + 6 = 6x + 21 = 3(2x + 7) Do you always have to use the distributive property or can you just divide by the number?
How do you simplify 8x-6+x-1? - Socratic
2016年5月26日 · It is 9x-7. The rule is that the numbers goes with numbers and the letters goes with the letters. So first of all you can reorder them as 8x+x-6-1. The part with the numbers is …
How do you find the slope and intercept of y = 6x + 1? | Socratic
2018年3月25日 · Since 6 is essentially #6/1# we know that the slope goes up 6 units. and right 1 unit on a graph. Next, #color(blue)"to find the y-intercept"# of y=6x+1, you substitute x as …
Polynomials in Standard Form - Algebra - Socratic
The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=-3, how do you find a possible formula for P(x)? The …
Equations of Parallel Lines - Algebra - Socratic
What is the slope of a line that passes through the point (−1, 1) and is parallel to a line that passes through (3, 6) and (1, −2)? How do you write the equation of the line parallel to …
How do you write the equation #y-5=6(x+1)# in slope ... - Socratic
2017年6月12日 · First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis: y - 5 = …
Find roots of x^6-×-1 - Socratic
2018年6月5日 · See roots below. x^6-x-1 =0 This degree 6 polynomial will have 6 real and/or complex roots. Using the ...
How do you solve #6/(x-1) = 9/(x+1)#? - Socratic
2016年10月5日 · Since a denominator cannot never be zero we have to find the #x# values that make it zero and exclude them from the solutions of the equation. # (x-1)(x+1)=0# This is a …