2015年9月25日 · 20x^2sqrt(2x) Prime factors of 50 are 2 * 5 * 5 And x^5 = x^2 * x^2 * x Hence: 4sqrt(50x^5) = 4sqrt(2 * 5 * 5 * x^2 * x^2 * x) Since sqrt(5*5) = 5 and sqrt(x^2 * x^2) = x^2 4sqrt(50x^5) = 4*5*x^2sqrt(2*x) = 20x^2sqrt(2x)

2018年3月8日 · Break the trinomial into two binomials and solve for x in each of the binomials x^2 + 15x + 50 = ( x +5)xx( x +10 ) so (x + 5) xx ( x +10 ) = 0 x + 5 = 0 subtract 5 from both sides x + 5 - 5 = 0 -5 x = 5 x + 10 = 0 subtract 10 from both sides x + 10 -10 = 0-10 x = …

How do you add #4.5 x 10^4# and #3.0 x 10^5#? How do you write 153200 in scientific notation? How do you multiply #470000000 * .000035# using scientific notation?

2018年4月11日 · 250 since we know 20% can also be written as 20/100, insert that into a cross multiplication scenario to determine x 50/x = 20/100 reduce the fraction on the right 50/x = 1/5 cross multiply 1(x) = 5(50) x = 250

2018年5月14日 · 1st, we need to convert #7.50# x #10^23# molecules into moles #7.50# x #10^23# molecules x #(1mol)/(6.02x10^23)# = #1.25mol# Now we convert #1.25mol# to grams #(g)# #1.25cancel(mol# x #(98g)/(1cancel(mol)# = #122.5g# Note, when converting to grams, its gram formula mass / #1mol#. The formula mass is all the element's masses added together ; …

2018年6月21日 · What is the direct variation equation if y varies directly with x, and #y=7.5# when #x=2.5#? What is the direct variation equation if y varies directly with x, and #y=2# when #x=4#? See all questions in Direct Variation

2015年10月24日 · We can start from the power series that you were taught during the semester: 1/(1-u) = sum_(n=0)^(N) u^n = 1 + u + u^2 + u^3 + ... Now, let's work from ln(5-x) to get to 1/(1-u). d/(dx)[ln(5-x)] = -1/(5-x) = -1/5*1/(1-x/5) Thus, with u = x/5, we had just taken the derivative and then factored out -1/5. To get the power series, we have to work backwards. We had done …

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2017年11月4日 · The easiest one is: #1/2 = 0.5 = 0.50 = 50/100 = 50%# #5/6# can be written as #5 div 6# If you do the division you will end up with a decimal: #5/6 = 0.8333333....# The first two decimal places represent hundredths. #0color(blue)(.83)3333... = (color(blue)(83).333)/100 = 83.3333..%# You can give this rounded to a chosen number of decimal places:

2018年3月9日 · 6.67 * 10^14 Hz wave equation: s = flambda speed = wavelength * frequency where s is in metres per second m//s f is in hertz Hz and lambda is in metres m. s = flambda can be rearranged as f = s/lambda here, s = 3 * 10^8 m//s and lambda = 4.5 * 10^-7 m s/lambda = (3 * 10^8)/(4.5 * 10^-7) 3/4.5 = 2/3 ~~ 0.667 10^8 / 10^-7 = 10^(8 - -7) = 10^(8+7) = 10^15 0.667 * …