2016年11月14日 · I got 1.23 We can use our usual algorithm for multiplication putting the numbers in column and multiplying; at the end we have to introduce a decimal point accordingly:

2018年3月9日 · Rasputin ran 32 miles and walked 9 miles. Let Rasputin ran x miles at 8 mph and walked 41-x miles at 3 mph . He took total 7 hours to complete. Time taken on running is x/8 hours and time taken on walking is (41-x)/3 hours . :. x/8+(41 -x)/3=7. Multiplying by 24 on both sides we get , 3x+8(41-x)=7*24 or 3x+328-8x=168 or -5x= 168-328 or 5x=160 :. x=160/5=32 …

#color(blue)(y=f(x)=(x-3)^2+8#, where. #color(green)(a=1; h=3; k=8# Hence, #color(blue)("Vertex "= (3, 8)# To find the y-intercept, set #color(red)(x=0# #y=(0-3)^2+8# #y=9+8# #y= 17# Hence, the y-intercept: #color(blue)((0, 17)# We can use a table of values to draw the graph: Use the table with two columns #color(red)(x and y# to draw the graph ...

2016年3月27日 · #5x-15+2x=41# We can combine our variables on the left to get #7x-15=41# To get our constants on one side, we can add #15# to both sides. We now have the equation #7x=56# Lastly, to completely isolate the variable, we can divide both sides by #7#. We get. #x=8# Hope this helps!

Solving concept. To solve a trig equation, transform it into one, or many, basic trig equations. Solving a trig equation, finally, results in solving various basic trig equations.

This integral can be solved by using the Partial Fractions approach, giving an answer of #2ln(x+5)-ln(x-2) + C#

2016年6月21日 · (7x-2)(3x-5) The following is a lengthy, annoying method that doesn't require any guessing of factor pairs, as per the usual method of factoring: Reorder the terms: p(x)=21x^2-41x+10 Factor 21 from the first two terms. p(x)=21(x^2-41/21x)+10 Complete the square inside the terms you previously factored the 21 from. Since perfect squares come in the form (x …

2015年7月20日 · 7.41xx10^(-5)=0.0000741 In order to expand 7.41xx10^(-5) into standard notation, the exponent -5 indicates that the decimal should be moved to the left 5 places to get 0.0000741.

We write #x^2+6x+9-9# If we group it this way: #(x^2+6x+9)-9# then we have a perfect square minus #9# And #(x^2+6x+9)-9=(x+3)^2-9# Solving an equation by completing the square: Solve: #x^2+6x-16=0# (by completing the square) Each of the following equations is equivalent (has exactly the same solutions) as the lines before it. #x^2+6x-16=0 # #x ...

2016年12月4日 · int_40^41xsqrt(x-40)color(white).dx=406/15 >I=int_40^41xsqrt(x-40)color(white).dx We should apply the substitution u=x-40. This implies that x=u+40 and that du=dx. When doing the substitution, plug the current bounds of x=40 and x=41 into u=x-40. These give bounds of x=40=>u=40-40=0 and x=41=>u=41-40=1. Thus: …