Jul 27, 2016 · To solve the quadratic equation 40 − x 2 = 0, we first rearrange it to the standard form of a quadratic equation, which is a x 2 + b x + c = 0. In this case, we can rewrite it as x 2 = 40. Next, we take the square root of both sides: x = ± 40 Calculating 40 , we can simplify it: 40 = 4 × 10 = 2 10 Thus, we have x = ± 2 10 . To find the ...

Oct 24, 2024 · x − 2 = 3 − 40 x = 2 + 3 − 40 x ≈ 2 − 3.42 ≈ − 1.42 Step 3: Find the intercepts Now, we check where the original graph intersects the x-axis. Setting f ( x ) = 0 gives us the same equation, which indicates that the x-intercepts we will work with from the original function are at the roots we need to calculate.

Oct 8, 2019 · For example, if we choose x = 2 10 , we can substitute back into the original equation to verify: 40 − (2 10 ) 2 = 40 − 40 = 0, confirming that our solution is correct. Similarly, for x = − 2 10 , the calculation yields the same outcome because squaring a negative number gives a …

Nov 14, 2023 · To solve the quadratic equation provided, which is given as 40 − x 2 = 0, we start by rearranging it into a standard form. 40 − x 2 = 0 can be rewritten as x 2 − 40 = 0 or x 2 = 40. Next, we can find the values of x by taking the square root of both sides: x = ± 40 Now, we simplify 40 . It can be factored as follows: 40 = 4 ⋅ 10 = 4 ...

Apr 4, 2016 · The answers for x^2+3x−40=0 are -8 and 5. For this problem, we are able to factor. Since 8 and 5 are both factors of 40, and since 8-5=3, we will use 8 and 5 in our binomial equation: (x+8)(x-5)=40. Just to prove that this is correct, let's multiply the two together: x^2-5x+8x-40=x^2+3x-40. From here, we can use the zero product property to get our answers: …

Dec 10, 2024 · x = 0: Generally, having a dimension of zero would result in a volume of zero, which wouldn’t match the given 40 cubic meters, so this option is less likely to be correct. Conclusion: Given the constraints and options, the values x = − 2 and x = 2 are consistent with solutions typically needed to reach a specific volume under similar ...

To find the quotient and remainder using partial fractions, we first perform polynomial long division to divide 2x^3 - 25x + 40\) by \(x^2 + 2x - 8\ The division looks like this: 2 x + 6. x 2 + 2 x − 8∣2 x 3 − 25 x + 40 − (2 x 3 + 4 x 2 − 16 x) − 29 x + 40 − (− 29 x − 58) 98. So, 2x^3 - 25x + 40 = (2x + 6)(x^2 + 2x - 8) - 29x ...

Mar 5, 2018 · To convert the quadratic function f (x) = x 2 + 14 x + 40 into vertex form, we need to complete the square. The vertex form of a quadratic function is given by f (x) = a (x − h) 2 + k, where (h, k) is the vertex of the parabola. Start by rewriting the function: f (x) = x 2 + 14 x + 40. Isolate the constant term: f (x) − 40 = x 2 + 14 x ...

Jul 31, 2017 · The polynomial 12 x 4 + 17 x 3 + 8 x − 40 divided by x + 2 yields a quotient of 12 x 3 − 7 x 2 + 14 x − 20 with a remainder of 0. This means the division is exact with no leftover term. This means the division is exact with no leftover term.

The correct representation of the** re-grouping f**or 45 x 12 is: 40 x 10; 5 x 10; 40 x 2; 5 x 2. This method is a way of breaking the** multiplication **down to enable easier calculation: 40 x 10 is 400, 5 x 10 is 50, 40 x 2 is 80 and finally 5 x 2 is 10. If you add all these together (400 + 50 + 80 + 10), you get 540 which is the result of 45 ...