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2016年11月2日 · x= 0, -4 x(x+4) = 0 x/x(x+4) = 0/x x+4 = 0 x+4-4 = 0-4 **x = -4** x(x+4) = 0 x((x+4)/(x+4)) = (0/(x+4 )) **x = 0**

2018年6月22日 · x in(-3,4) graph{(x-4)(x+3)<0 [-3.22, 4.576, -2.05, 1.85]} we have (x-4)(x+3)<0 from here we get two critical points i.e X=4,-3 these are the values on which the sign of the equation changes to get a range for x mark these critical points on a real number line take any value between -3 and 4 (lets say 0) (0-4)(0+3)<0 always hence this part (-3,4) satisfies the …

2017年4月4日 · = cis ((-pi)/8 ), cis ((3pi)/8 ), cis ((7pi)/8 ), cis ((11pi)/8 ) x^4 = - i x = (- i)^(1/4) Using Euler's formula (or DeMoivre's theorem, if you like): -i = cos ((-pi ...

2016年11月15日 · How do you find the area between #g(x)=4/(2-x), y=4, x=0#? Calculus Using Integrals to Find Areas and Volumes Calculating Areas using Integrals 1 Answer

2016年7月31日 · One of the properties of zero is that "Anything times 0 is equal to 0" So, # a = 0, or b=0, or c=0, or d=0.# To have a 0 from multiplying means we must start with a 0. In #(x-4)(x-3)=0" "# we have the product of two factors equal to 0, ONE of them MUST be 0. If #x-4 = 0" "rArr x = 4# If #x-3 = 0" "rArr x = 3# These are the two solutions.

2019年5月3日 · Find the mean and standard deviation for the random variable x given the following distribution Answers · 3 using interval notation to show intervals of increasing and decreasing and postive and negative

2018年2月11日 · make x the subject of the formula. x - 4 = 0 add 4: x = 0 + 4 x = 4 graph as a vertical line, where x is the constant 4.

2015年8月24日 · d/dx(4^x) = 4^x ln4 In general for b>0, we have d/dx(b^x) = b^x lnb And when we need the chain rule, we have d/dx(b^u) = b^u (lnb) d/dx(u) Proof of General rule b^x = (e^lnb)^x " " (remember that e^lnu = u) So b^x = e^(xlnb) " " (because (a^r)^s = a^(rs) = a^(sr)) d/dx(e^(xlnb)) can be found by the chain rule: d/dx(e^(xlnb)) = e^(xlnb) d/dx(xlnb) = e^(xlnb) …

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