Jan 18, 2016 · x=4 or x=-4 First divide throughout by 2 to get x^2=16 Now take the square root on both sides to get x=+-4. You may now substitute the values of x=4 and x=-4 back into the original equation and check that it satisfies the equation which it does.

Oct 26, 2015 · x= 5 or -1 Looking at your format I assume you meant to write: 2^ (x^2) = 32 (2^(4x)) => (2^ (x^2))/(2^(4x)) = 32 => 2^((x^2 - 4x)) = 32 Taking logs: =>(x^2 - 4x)log ...

Mar 22, 2018 · x=4sqrt(2)" " Exact answer for principle root x=+-4sqrt(2)" " As a full exact answer x+-5.6569 to 4 decimal places - Approximate answer Consider the 32. We are looking for squared number we can 'take outside' the root 32 is even so we have 2xx16 But 16 is 4^2 giving 2 xx 4^2. So we can write: x=sqrt(2xx4^2) x=4sqrt(2) Using the Principle Root which is always positive.

Jan 10, 2016 · -32/x^2 Before differentiating this function it requires to be written in the form ax^n note that the derivative of a function must be in the correct form before you can differentiate it. f(x) = ax^n rArr f'(x) =nax^(n - 1 ) 32/x = 32x^-1 now differentiating gives -1xx32x^-2 rewriting with a positive index the gives -32/x^2

Apr 8, 2017 · Solutuion : x= 1 + sqrt 33 or x= 1 - sqrt 33 x^2-2x=32 or x^2-2x +1 =32 +1 or (x -1)^2 =33 or x -1 = +- sqrt 33 or x= 1 + sqrt 33 or x = 1 - sqrt 33 Solutuion : x= 1 ...

Jun 22, 2016 · 24003 views around the world You can reuse this answer ...

Mar 9, 2016 · x=5 The logarithmic expression can be exponentiated with a base of 2: 2^(log_2 32)=2^x The 2^x and log_2 x functions are inverses, which means that they undo one another, so we obtain the equation: 32=2^x We can write 32 as a power of 2: 2^5=2^x Since the bases are equal, we know their powers are also equal, giving: x=5

Mar 21, 2016 · color(blue)((x + 2) ( x -16) is the factorised form of the expression. y = x^2 - 14x - 32 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like ax^2 + bx + c, we need to think of 2 numbers such that: N_1*N_2 = a*c = 1 * (-32) = -32 AND N_1 +N_2 = b = -14 After trying out a few numbers we get N_1 = -16 and N_2 =2 (-16 ...

Nov 23, 2015 · color(blue)((x-4)(x-8) is the factorised form of the expression. x^2-12x+32 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like ax^2 + bx + c, we need to think of 2 numbers such that: N_1*N_2 = a*c = 1*32 =32 AND N_1 +N_2 = b = -12 After trying out a few numbers we get: N_1 = -8 and N_2 =-4 (-8)*(-4) = 32, and (-8) +(-4 ...

May 20, 2016 · -32/x^2 >Begin by expressing 32/x=32x^-1 differentiate using the color(blue)"power rule" d/dx(ax^n)=nax^(n-1) rArrd/dx(32x^-1)=-1xx32x^-2=-32/x^2