
Explain the difference between sin^-1(x) and 1/sin(x), Are ... - Wyzant
2015年4月28日 · In sin-1 x, the "-1" is NOT an exponent. It represents the inverse of the sine function. Recall f(x) and f-1 (x).
When do I use sin^-1 and when do I just use sin? - Wyzant
2019年4月25日 · Please see below. sin-1 is used when you are trying to find the Angle that corresponds to a given Sine. sin( ) is used when you are trying to find the Sine of a given angle
Is arcsin(x)=1/sin? | Wyzant Ask An Expert
2018年12月27日 · No, (1 / sin x) = csc x This identity should be memorized. arcsin is the inverse relation of the sin. E.g., sin 30° = 0.5
Cos/1+sin + 1+sin/cos = 2sec | Wyzant Ask An Expert
2014年12月3日 · Cos/1+sin + 1+sin/cos = 2sec , and cos = 0.866025, sin = 0.500, tan = sin/cos = 0.57735, and sec = 1/cos ...
formula of 1+sin2x | Wyzant Ask An Expert
2017年1月13日 · 1+sin2x = 1+2sinxcosx = sin^2x + cos^2x + 2sinxcosx = (sinx + cosx)^2 = an alternate way of expressing 1+sin2x -> if this is what you were looking for.
Explain why sin?^2 + cos?^2=1 | Wyzant Ask An Expert
2015年10月28日 · Let θ be an angle in standard position with vertex at (0,0). Let (x, y) be a point on the terminal side of θ and let r be the distance from (0,0) to (x,y).
Simplify (1+sin(t)) / (1+csc(t)) - Wyzant
2015年11月21日 · 1+csct=1+1/sint=(sint+1)/sint (write 1 as sint/sint and add the two fractions)
Verify (1+sin^2x)/cos^2x=1+2tan^2x | Wyzant Ask An Expert
2020年10月21日 · (1+sin^2)/cos^2= 1 +2(sin^2)/cos2 [find common denominator onthe left side and change tan^2 to sin^2/cos^2
integral 1/ (sin (x)+cos (x)) | Wyzant Ask An Expert
2013年1月7日 · Abdallah K. To solve this integration multiply the integration by (1/square root of 2) so you could multiply the denominator by cos(pi/4) with the sin(x) and by sin(pi/4) with the cos(x). afterwards the denominator equals sin((pi/4)+x) .
How do you solve cos(Sin^-1(2x))? - Wyzant
2014年8月15日 · first determine the lengths of all the sides of a right triangle using the information inverse sin (arcsin) of 2x.