consider the general quadratic equation $ax^2+bx+c=0$ with real coefficients. we have a formula for finding its both the roots.

2019年1月12日 · I've been having trouble with this quadratic equation where $6639.55 = -0.06493x^2 + 22.35175x + 5065.25 ...

Hope it is a right place to ask how to solve the equation on $\mathbf x$: $$ \mathbf x^T \mathbf A\mathbf x + \mathbf x^T \mathbf b + c = 0.

2018年4月30日 · The quadratic equation has no real roots since its discriminant $\Delta = b^2 - 4ac = 5^2 - 4 \cdot 2 \cdot 4 = -7 < 0$. $\endgroup$ – N. F. Taussig Commented Apr 30, 2018 at 1:31

2021年4月6日 · I just watched a video that teaches a trick to solve some quadratic equations faster: Suppose we have $3x^2-152x+100=0$ It takes a lot of time to solve it by finding discriminant because we have to

2015年5月12日 · $\begingroup$ elimination and matrix methods are simply flavours of the same thing really, as are using the equation or completing the square for a quadratic. $\endgroup$ – Paul Commented May 12, 2015 at 12:46

2021年8月2日 · In this approach , what matters is that in the starting $3 \cdot 2$ ( this $-5x$ which we shortened up into $-3x-2x$) should be equal to $6$, i.e. our constant in the quadratic equation. Even in 2nd case, $6 \cdot 1 = 6$ .

2016年4月20日 · I was bothered with the following very simple problem: Solving a quadratic equation $x^2+x+1=0$ in mathematica if I use "solve" function in mathematica as below ...

2018年5月15日 · I have a problem where I am to find the intersection between the two curves $$ \begin{cases} x^2 - y^2 = 3 \\ xy = 2, \end{cases} $$ which I can easily see that the two points $\pm(2,1)$ are the real solutions to this problem, but I don't know how to solve for this systematically. I tried two approaches to solve for it as a quadratic equation:

2018年1月30日 · Calculus approach to solve this Quadratic equation problem. 1. System of two quadratic equations. 0.