2016年7月21日 · You can use some basic trigonometry identities and some substitution to convert one form into the other. Given that r is the distance from the origin -- basically the length of the hypotenuse of a triangle whose legs are of length x and y -- and that theta is the angle from the x-axis up to hypotenuse, you can draw from basic trigonometry the following relationships: x = …

2016年6月9日 · The equation y = 6x - 2 is in this form and by inspection. slope = 6. Answer link. Related questions.

2018年7月8日 · #y=6x^2-24x+16# and this is. #y=6(x^2-4x+16/6)# #y=6(x^2-4x+8/3)# now we complete the square. #y=6(x^2-4x+4+8/3-4)# we use that . #x^2-4x+4=(x-2)^2# and #8/3-4=8/3-12/3=-4/3# so we get. #y=6(x-2)^2-6*4/3# the result is …

2017年12月9日 · Graph of y = 6x^2 is available as part of this solution. Vertex = (0,0) Axis of Symmetry is the line x = 0 x-intercept x =(0,0) We are given the quadratic equation y = 6x^2 color(red)(..Equation.1) Graph of the Quadratic Equation y = 6x^2 is below: Let us investigate the graph: How do we find the X Intercept? To find the x-intercept of the equation we let y = 0 and …

2017年4月6日 · Use A = int_a^b(y_1(x)-y_2(x))dx where y_1(x) >= y_2(x) Find the x coordinates of endpoints of the area. 6x - x^2 = x^2- 2x 0 = 2x^2-8x x = 0 and x = 4 This means that: a = 0 and b = 4 Evaluate both at 2 and observe which is greater: y = 6(2)-(2)^2 = 8 y = 2^2 - 2(2) = 0 The first one is greater so we subtract the second from the first in the integral: int_0^4(6x-x^2) - …

What is the y coordinate of the vertex of a parabola #y=x^2-6x+14#? How do you find the vertex of a parabola given by the equation #x = y^2 - 4y + 3#? What is the vertex parabola #y=2 (x-3)^2+4#?

2017年11月29日 · First, think of y>6x-2 as y=6x-2 and graph the slope, which has the y -intercept of -2 and the slope of 6/ ...

y=6x^2-4 (original function) To find the inverse, interchange x and y and solve for y x=6y^2-4 x+4=6y^2 y^2=(x+4)/6 y=+-sqrt((x+4)/6) (inverse function) y=+-((x+4)/6)^.5 see the graph of the original function and its inverse below: The green and blue curves make up the inverse function. As you can see, it is not a function because for each x in ...

Question 384618: Given the linear equation y = -6x – 2, find the y-coordinates of the points (-1, ), (-2, ), and (1, ). Please show all of your work. Please show all of your work. Plot these points and graph the linear equation.

2015年7月5日 · The normal revolution method calls for: V = pir^2h = sum_(a=a_0)^b pi(r(x))^2Deltax = piint_a^b (r(x))^2dx where one stacks circle analogs of varying radius r(x) across an orthogonal interval Deltax. In contrast, the shell method calls for a volume formula as such: V = int_a^b 2pixr(x)dx where the way r(x) varies determines the height and shape of the …