2015年8月12日 · #x^2-4x=0# Here #color(blue)(x# is common to both the terms of the expression. #color(blue)(x)(x-4)=0# Now we equate each of the two factors to zero, to obtain the solutions.

2016年7月23日 · x = -0.586 " or "x = -3.414 x^2 +4x + 2=0 cannot be factored because there are no factors of 2 which add up to 4. It can be solved by the method of completing the square or the quadratic formula.

2018年5月5日 · x in RR (x+2)^2=x^2+4x+4 Factor right side, (x+2)^2=(x+2)^2 Square root both sides, x+2=x+2 Move like-terms together, x-x=2-2 Simplify, 0x=0 Since, both sides are similar, we can denote that, x in RR

2018年3月4日 · The quadratic formula states:. For #color(red)(a)x^2 + color(blue)(b)x + color(green)(c) = 0#, the values of #x# which are the solutions to the equation are given by:

2016年7月12日 · x = 6 and x = -2 By moving 4x to the left of our equation, we can then complete the square in the following way: x^2 = 4x + 12 x^2 -4x = 12 We take the coefficient on the x-term, namely -4, divide it by 2, and square the result, giving us (-4/2)^(2) = (-2)^2 = 4 Since our goal is to rewrite our equation in the form of x^2 -4x + ? = 12 + ? We replace our ? marks with the …

2017年7月13日 · See a solution process below: First, expand the terms in the right parenthesis by multiply each term within the parenthesis by the term outside the parenthesis: (x + 5) - color(red)(2)(4x - 1) = 0 (x + 5) - (color(red)(2) xx 4x) + (color(red)(2) xx 1) = 0 (x + 5) - 8x + 2 = 0 x + 5 - 8x + 2 = 0 x - 8x + 5 + 2 = 0 1x - 8x + 5 + 2 = 0 (1 - 8)x + (5 + 2) = 0 -7x + 7 = 0 Next, …

2016年8月2日 · 2(x+1)^2-7 We begin with y=2x^2+4x-5. We need to rewrite this into vertex form. The easiest way to do that is to complete the square. This is a very useful way to factor, and I don't want to spend too much time explaining it right now, but I'll cover it as I go. In order to begin completing the square we need to factor the equation until the leading coefficient (meaning a …

2018年6月1日 · Find the intercepts and the vertex. Set x=0 to find the y intercept: y = x^2 + 4x + 1 y = 0^2 + 0x + 1 y=1 Set y=0 to find the x intercept(s) if they exist: y = x^2 + 4x + 1 0 = x^2 + 4x + 1 use the quadratic formula: x = (-b+-sqrt(b^2 -4ac))/(2a) x = (-4+-sqrt(4^2 -4*1*1))/(2*1) x=2+-sqrt3 Now find the Axis of Symmetry (aos): aos = -b/(2a) = (-4)/(2*1) = -2 Find the vertex: …

2015年11月17日 · x^2 - 4x - 12=color(green)((x-6)(x+2) color(red)(x^2 - 4x - 12 We can Split the Middle Term of this expression to factorise it In this technique, if we have to factorise an expression like ax^2 + bx + c, we need to think of 2 numbers such that: N_1*N_2 = a*c = 1*-12 = -12 AND N_1 +N_2 = b = -4 After trying out a few numbers we get N_1 = -6 and N_2 =2 -6*2 = …

2016年1月28日 · Sort the x terms and y terms so that they are near one another. x^2+4x+y^2+6y=-4 Now, complete the square for each part by adding constants. Remember that a constant added on the left side should also be added on the right to keep the equation balanced. (x^2+4x+color(red)4)+(y^2+6y+color(blue)9)=-4+color(red)4+color(blue)9 This …