2009年5月1日 · The value of *t++ is the character that t pointed to before t was incremented; the postfix ++ doesn't change t until after this character has been fetched. In the same way, the character is stored into the old s position before s is incremented.

2013年1月10日 · At first, your code will be in infinte loop because of the below line. you were supposed to use curely braces by including "p++; t++ " statements. while(*t!='\0') *p=*t; though you do like this, you are trying to alter the content of the string literal. which will result in undefined behavior like segmentation fault.

2012年1月12日 · while (*s++ == *t++) { ... The important difference is that in the first case s and t are incremented at the end of the loop body, whereas in the first case they are incremented at the start of the loop body.

2012年4月3日 · t++; in the above code will increment the address of array a by 1 char in the calling function test. Fine, now as far I know the * is used to retrieve the object value that the pointer points to. But weirdly when I change the t++ to *t++; I'm getting the same output as before.

2013年5月22日 · while (*i && *i++ == *t++); to stop at the 0-terminator. But that will fail if there is a mismatch at the last character before the 0-terminator, since then both pointers will still be incremented, and i points to the terminator, so better use

while(*s++=*t++) *t will be assigned to *s *s will be checked as the condition *s and *t will be incremented; A, C: The value of *s and *t would only change and incremented if the condition is fulfilled (At least 1 increment in original code).

2014年7月3日 · Although *s++ = *t++ is unfortunately a rather commonly encountered line in C, I just want to point out the following: Using ++ together with other operators in the same expression is dangerous practice.

2015年9月8日 · When you use. while (*s++ != '\0'); s points to one character past the null character when the loop breaks. You end up copying the contents of t to s but after the null character.

The expression *s++ = *t++ still has a result, and that result that can be used as a condition. More precisely, the result will be the character copied, and as you (should) know all non-zero values are considered "true", and as you also (should) know strings in C are zero terminated.

2014年2月2日 · Write a pointer version of the function strcat that we showed in Chapter 2: strcat(s, t) copies the string t to the end of s.