Question: 1.) Pb(NO3)2 + NaI → PbI2 + NaNO3 When 35 grams lead (II) nitrate reacts with 300 grams of sodium iodide, sodium nitrate and lead (II) iodide are formed. a. What is the balanced equation? b. What is the limiting reactant in the production of NaNO3? c. What is the theoretical yield of NaNO3? d. What is the percent yield of NaNO3? e.

Question: Dissociation of PbI2: PbI2(s) ↔ Pb2+(aq) + 2I-(aq). Which of the following would decrease solubility of PbI2? Which of the following would decrease the Ksp for PbI2? A. Lowering the pH of the solution B. Adding a solution of

Answer to DETERMINING THE SOLUBILITY PRODUCT OF PbI2 In this. DETERMINING THE SOLUBILITY PRODUCT OF PbI2 In this experiment, you will determine the solubility product (Ksp) of lead iodide Pblz (s) = Pb2+ (aq) + 21-(aq) Ksp = [Pb2+]".

Given Pb (NO3) 2 (aq) + 2 KI (aq) = PbI2 (s) + 2 KNO3 (aq) Moles of Pb (NO3)2 = .0104 Moles of KI = .0020 Which is the limiting reagent? How much lead(II) iodide will be produced (theoretical yield). Show your process and results in the space below. Type out your calculations

Question: 22. Lead(II) iodide, PbI2, is a slightly soluble salt with a KSP value of 9.8 x 10-9. The equation for its dissociation in water is PbI2(s) <-----> Pb2+(aq) + 2I-(aq) What is the molar solubility of PbI2 in distilled water? 23. In the previous problem, you calculated the molar solubility of PbI2 in distilled water.

only PbI2, and PbS only PbCO3 and PbI2 only PbCO3, PbI2, and PbS only PbCO3 and PbS Consider the following salts: PbCO 3 , PbCl 2 , PbI 2 , and PbS. Which salts would be more soluble in acidic aqueous solution than in pure water?

For the reaction 2KI+Pb(NO3)2 PbI2+2KNO3 how many grams of lead(II) nitrate, Pb(NO3)2, are needed to react completely with 83.7 g of potassium iodide, KI?

how many grams of lead (ii) iodide, pbi2, are produced from 71.7 g of potassium iodide, KI? Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

Determination of the solubility product of PbI2. From the experimental data we obtain [I-] directly. To obtain Ksp for PbI2, we must calculate [Pb2+] in each equilibrium system. This is most easily done by constructing an equilibrium table. We first find the initial amount of I- and Pb2+ ion in each system from the way the mixture were made up.

PbI2 = Spell out the full name of the compound. PbI 2 = There are 2 steps to solve this one. Solution ...