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1 1 4 0 -4 0 -5 -1 -8 I3 = 3x3 identity matrix λ 0 0 λI3 = 0 λ 0 0 0 λ λ-1 -1 -4 = 0 λ+4 0 5 1 λ.... $\begingroup$ Note that similar matrices have the same trace.Therefore it cannot be A. And you also know that, if there exists a diagonal matrix, then the sum of diagonal elements must be $-11$ and only numbers $-4$ and $-3$ are allowed on diagonal.

2020年6月17日 · Linear algebra - diagonizable matrix: find matrix P and D such that A = PDP^-1 Hot Network Questions Tufte-Handout documentclass produces empty first page with titleheader if maketitle is included in fullwidth environment

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2020年6月16日 · Provide a P and a diagonal matrix D such that A = PDP^-1. Given: A= \begin{array}{l}-1-5i&1+2i&1+7i\\-4-14i&3+6i&1+19i\\-6+4i&3-2i&5-5i\end{array} λ=1−i, 2−3i, 4. The matrix P would be: ____ The matrix D would be: ____ So I'm struggling to figure out how I would find the P and D matrices from matrix A.

We just crammed spectral decomposition into our last lecture of the quarter, and I'm quite confused by it. The following question is on my homework: Use the matrices P and D to construct a spectral

2015年8月11日 · $$ P^{-1} = \begin{bmatrix} 2 & 1 \\ -3 & -2 \end{bmatrix} $$ I try to multiply them together to check that I get the same as my original matrix, but I seem to get the wrong values (but tantalisingly close).

2018年10月17日 · A matrix A is called orthogonally diagonalizable if $A=PDP^{-1}$ and $A=PDP^{T}$, where $D$ is diagonal. Therefore, $P^{-1}=P^T$ and thus $P$ is an orthogonal