2015年7月12日 · $\begingroup$ Notice that after one full turn the change in position is also zero. What we are interested in here really the average value of the instantaneous acceleration, but …

2022年4月30日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …

2020年9月3日 · So, from Newton's second law, we know that an inward force $\frac{mv^2}{r}$ must act on it. This inward force is gravity, whose magnitude is $\frac{GMm}{r^2}$ . Therefore, …

2016年11月17日 · What is the proof for kinetic energy $= \dfrac{mv^2}{2}$? Work done= mass × acceleration × displacement $$=m\times a\times s$$

2017年4月16日 · In your case, you won't find the same value because when you assume this equality $\frac{mv^2}{r} = \frac ...

2015年6月22日 · So: $ (mv^2)/r \le \mu_s mg $ In other words, with this equation you can calculate the maximum speed as you correctly observed. However this equation is used for …

2015年6月21日 · The proper derivation of the centripetal acceleration—without assuming any kinematic variables are constant—requires a solid understanding of both the stationary …

2015年6月21日 · There are several ways to write centripetal acceleration $$\frac{v^2}{r} = \omega^2 r = v \omega$$ Are there intuitive explanations for any of these three forms?

2019年1月26日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …