Double the H2O to get 4 on the left side. Now you need a 4th H on the right side, so double the LiHCO3. That balances H, but you need to double the Li on the left side Also you need more C on the left so double the CO2. That balances H, Li, C, and O. Just double everything in the original reaction, except for the H2 on the right.

2019年3月25日 · Li2CO3(aq) + MgCl2(aq) → MgCO3(s) + 2LiCl(aq) 2Li+ + CO3 -2 + Mg2+ + 2Cl- → Mg2+ + CO3 -2 + 2Li+ + 2Cl-

2021年7月7日 · CH 4 (g) + H 2 O(g) → CO(g) + 3 H 2 (g). This reaction is the only one that has ∆S > 0 because it shows 2 moles of gas on the reactant side going to 4 moles of gas on the product side.

2017年10月19日 · µ · • § ¶ ß ‹ › « » < > ≤ ≥ – — ¯ ‾ ¤ ¦ ¨ ¡ ¿ ˆ ˜ ° − ± ÷ ⁄ × ƒ ∫ ∑ ∞ √ ∼ ≅ ≈ ≠ ≡ ∈ ∉ ∋ ...

2022年11月1日 · Enter the balanced complete ionic equation for the acid-base reaction with the weak acid, acetic acid. HC2H3O2(aq)+LiOH(aq)→

Holly B. asked • 09/18/18 Given the following balanced equation: H3PO4(aq) + 3 KOH(aq) → K3PO4(aq) + 3 H2O(l) How many grams of potassium hydroxide are required to completely neu