
Complex Numbers & Phasors in Polar and Rectangular Form
A number with the letter ” j ” in front of it identifies it as an imaginary number in the complex plane. By definition, the j-operator j ≡ √-1; Imaginary numbers can be added, subtracted, multiplied …
Complex number calculator - HackMath
As an imaginary unit, use i or j (in electrical engineering), which satisfies the basic equation i 2 = −1 or j 2 = −1. The calculator also converts a complex number into angle notation (phasor …
Complex Numbers - Basic Definitions - Interactive Mathematics
`(sqrta)^2 = a`, for any value of `a`. and `j = sqrt(-1)` Using these, we can derive the following: `j^2 = (sqrt-1)^2 = -1` Multiplying by `j` again gives us: `j^3 = j^2(j) = -j` Continuing the process …
j^2 - Wolfram|Alpha
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history, geography, …
Rocketdyne J-2 - Wikipedia
The J-2, commonly known as Rocketdyne J-2, was a liquid-fuel cryogenic rocket engine used on NASA's Saturn IB and Saturn V launch vehicles. Built in the United States by Rocketdyne, the …
Directorates > J2 | Joint Staff Intelligence - Joint Chiefs of Staff
The Directorate for Intelligence, J-2, supports the Chairman of the Joint Chiefs of Staff, the Secretary of Defense, Joint Staff and Unified Commands. It is the national level focal point for …
notation - $j^2 = 1$, but $j \neq \pm 1$; what is $j
Similar to the way that $i$ is $\sqrt{-1}$, but what that actually means is that $i^2$ is $-1$, $j^2$ is $+1$, but $j$ is not $1$. Here's the video with him saying all this - …
Mathway | Algebra Problem Solver
Free math problem solver answers your algebra homework questions with step-by-step explanations.
2. Basic Operations with Complex Numbers - Interactive …
Expand brackets as usual, but care with `j^2`! Example 2 - Multiplication . Multiply the following. a. `5(2 + 7j)` Answer
What's the Jordan form of $J^2$? - Mathematics Stack Exchange
2018年4月19日 · $$J^{2}v_{4} = v_{2}; \quad J^{2}v_{2} = 0$$ One cycle has length 3 and the other has length 2, meaning the Jordan form has a block of size 3 and a block of size 2. Also, …