
How can the Bonding in IF7 be explained using LCAO method?
A more accurate description of the bonding in in $\ce{IF7}$ Iodine heptafluoride is one of the classic examples when it comes to describing hypervalency and octet-expansion. Early attempts included d-Orbitals into describing that phenomenon (VSEPR), resulting in a description that yields the correct geometry.
Draw the structure of IF_7. Write its geometry and the of ... - Toppr
Draw the structure of xenon tetrafluoride molecule and state the hybridization of the central atom and the geometry of the molecule.
The shape of IF_{7} molecule is:pentagonal bipyramidaltrigonal
The central atom in I F 7 has seven pairs of valency electrons. The shape of the molecule as per VSEPR theory is:
Why an asymmetric geometry with sp3d and sp3d3 hybridization?
2015年5月17日 · For application of this concept to $\ce{SF6}$ see here. for $\ce{PCl5}$ see here and for $\ce{IF7}$ see here. $\endgroup$ – ron Commented May 17, 2015 at 15:21
quantum chemistry - Valence Bond theory, VSEPR theory and …
2017年7月25日 · When it comes to more complicated molecules, for example hyper-coordinated compounds like $\ce{IF7}$, most explanations (the involvement of d orbitals) break completely down and have been disproved many times. However, just by minimising the inter-ligand distances, it yield approximately the correct shape.
molecular structure - What is the highest possible expanded octet ...
2015年3月29日 · Some books will mention iodine heptafluoride, $\ce{IF7}$, as a seven-coordinate compound, with its pentagonal bipyramidal structure. It is still possible to add a fluoride and obtain an example of coordination number 8 in the octafluoroiodate(VII) anion, $\ce{IF8^{-}}$, which has an interesting square antiprismatic geometry (take a cube and ...
Hypervalency and the octet rule - Chemistry Stack Exchange
2015年4月22日 · If we count the electrons around iodine in $\ce{IF7}$ there are 4 in the two axial bonds (2x2) and 10 in the hypervalent equatorial bonds; a total of 14. However, 4 electrons are in a hypervalent non-bonding orbital and 2 more electrons can be viewed as being associated with a fluoride anion, leaving 8 bonding electrons, again, an octet.
How many bonded electron pairs are present in IF_7 …
You might have observed in C O 2 molecule, that there are two pairs of valence electrons on each of the oxygen atoms that are not bonded.
bond - PBP vs TBP geometry? - Chemistry Stack Exchange
2015年4月14日 · Why are the axial bond lengths greater than those of the equatorial bonds in a trigonal bi-pyramid (TBP) geometry molecule; but the opposite is true for pentagonal bi-pyramid (PBP) geometry molecul...
What is the structure of IF7 - Sawaal
In IF7 out of 7 Flourine atoms 5 of them are placed on a plane in Pentagon shape .In remaining 2 flourines one is placed above the plane and other below the plane each at 90 degrees Subject: Chemistry