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  1. Copilot 答案
    Construction

    The Fermat point of a triangle with largest angle at most 120° is simply its first isogonic center or X(13), which is constructed as follows:
    1. Construct an equilateral triangle on each of two arbitrarily … 展开

    Location of X(13)

    Fig. 2 shows the equilateral triangles △ARB, △AQC, △CPB attached to the sides of the arbitrary triangle △ABC. Here is a proof using properties of concyclic points to show that the three lines RC, BQ, AP in Fig 2 all int… 展开

    Location of the Fermat point

    Given any Euclidean triangle △ABC and an arbitrary point P let The aim of this section is to identify a point P0 such that for all If such a point exists then it will be the Fermat point. In what follows Δ will denote the points inside the … 展开

    Properties

    • When the largest angle of the triangle is not larger than 120°, X(13) is the Fermat point.
    • The angles subtended by the sides of the triangle at X(13) are all equal to 120° (Case 2), or 60°, 60°, 120° (Case 1).… 展开