2025年1月9日 · The force F on a conductor carrying current I in a magnetic field with flux density B is defined by the equation. F = BIL sin θ. Where: F = magnetic force on the current-carrying conductor (N) B = magnetic flux density of external magnetic field (T) I = current in the conductor (A) L = length of the conductor in the field (m)

\(\mathrm { F } = \mathrm { IlB } \sin \theta\) describes the magnetic force felt by a pair of wires. If they are parallel the equation is simplified as the sine function is 1. The force felt between two parallel conductive wires is used to define the ampere —the standard unit of current.

A current (I) in a magnetic field ( B) experiences a force ( F) given by the equation F = I l × B or F = IlB sin θ, where l is the length of the wire, represented by a vector pointing in the direction of the current. The direction of the force may be found by a right‐hand rule similar to …

Entering the given values into F = IlB sin θ yields. F = IlB sin θ = (20.0 A) (0.0500 m) (1.50 T) (1). This large magnetic field creates a significant force on a small length of wire. Magnetic force on current-carrying conductors is used to convert electric energy to work.

The force can be found with the given information by using F = IlB sin θ F = IlB sin θ and noting that the angle θ θ between I I and B B is 90º 90º, so that sin θ = 1 sin θ = 1. Solution. Entering the given values into F = IlB sin θ F = IlB sin θ yields

The force on the wire is given by F = IL × B. The direction of L × B is the negative y-direction. Since L and B are perpendicular to each other, the magnitude F = ILB. Details of the calculation: F = ILB = (2.4 A)(0.75 m)(1.6 T) = 2.88 N. The force on the section of wire is F = -2.88 N j, in the negative y-direction.

F = I ( L x B ) vector version = I L B sin(theta) strength only where theta is the angle between the wire and the magnetic field. The direction of the vector L is the same as the direction of the current through the wire.

Determine the magnitude and direction of the magnetic force acting on a 0.100 m section of the wire. Solution: The magnitude of the magnetic force can be found using the formula: \ (\begin {array} {l}\vec {F} {\rightarrow}=ILB\sin \theta \widehat {n}\end {array} …

The force on a current-carrying wire in a magnetic field is F = IlB sin θ. Its direction is given by RHR-1. Example 1. Calculating Magnetic Force on a Current-Carrying Wire: A Strong Magnetic Field. and noting that the angle θ between I and B is 90º, so that sin θ = 1. F = IlB sin θ = (20.0 A) (0.0500 m) (1.50 T) (1).

The force on a current-carrying wire in a magnetic field is F = IlB sin θ. Its direction is given by RHR-1. Calculate the force on the wire shown in Figure 1, given $latex \boldsymbol {B = 1.50 \;\textbf {T}} $, $latex \boldsymbol {l = 5.00 \;\textbf {cm}} …