May 3, 2012 · One of the formulas I came across while doing problems with simple parallel plate capacitors was E = V/d, where E is the magnitude of the electric field between the plates, V is the potential difference between the plates, and d is the separation of …

Feb 10, 2008 · A long glass filament carries a charge density [tex]\lambda = - 2.7{\rm{ nC/m}}[/tex] . What is the magnitude of the electric field 0.67 mm from the filament? The Attempt at a Solution Did I do this problem correctly? I'm guessing not because my answer has an extra /m . Shouldn't it simply be N/C? [tex]

Nov 12, 2021 · Determine the direction and magnitude of the electric field at a point P lying a distance ##x>0## from the center of the disc along the axis of symmetry of the disc. Relevant Equations I know how to solve this problem. The electric field vector points in only one direction, so there is really only one integral to do.

Aug 23, 2010 · Solve for the charge density given your original voltage (400 KV) and then substitute back into the electric field equation to find the actual fields. Of course though, for the specific question of the electric field strength at the ground it will be zero. But I have a feeling that there are a myriad of books that deal with the above problems.

Aug 18, 2012 · Homework Statement A proton (+e) accelerates from rest in a uniform electric field of 640 N/C. At some later time, the proton's speed is 1.20 x 10^6 m/s. Find the acceleration of the proton. The mass of a proton is 1.67x10^-27 kg. Charge on a …

Oct 25, 2012 · Electric field caused by a charge (or group of charges) is defined in terms of its effect on a test charge, given by the formula: E ⃗=lim┬(q_(0→0) )⁡〖F ⃗/q_0 〗 I understand that the point charge must be infinitesimally small in order not to affect the field in question, so it makes sense to take the limit of q[itex]_{0}[/itex] to 0.

Feb 20, 2014 · To calculate the electric field for a capacitor, you can use the formula E = V/d or E = λ/2πεr, depending on the type of capacitor. Simply plug in the values for potential difference, distance/charge density, and permittivity/radius to get the electric field strength.

Mar 13, 2016 · The beam is a form of electromagnetic raditation with both electric and magnetic field components. (a) Calculate the intensity of the beam in units of W/m^2 (b) Calculate the energy (delta U) delivered in a time of t = .065 s in Joules. (c) Use the intensity of the beam (I) to calculate the amplitude of the electric field in V/m

Feb 23, 2016 · 1) Find its rms electric field strength. 2) Find its rms magnetic field strength. Homework Equations Bo = Eo/c Brms = B/sqr(2) The Attempt at a Solution Answer to part 1 : Eo = 219 V/m Part 2 Calculate Bo = 219/2.998 x 10^8 = 7.3 x 10^-7 Brms = (7.3 x 10^-7)/sqr(2) = 5.17 x 10^-7 T This answer for part 2, doesn't match the expected answer.

Jul 2, 2010 · What is the direction of the electric field of a long line? The electric field of a long line is directed radially outward from the line, meaning it forms a cone shape with the line at its center. The direction of the field can be determined using the right hand rule, where the fingers point in the direction of the electric field and the thumb ...