2012年5月3日 · One of the formulas I came across while doing problems with simple parallel plate capacitors was E = V/d, where E is the magnitude of the electric field between the plates, V is the potential difference between the plates, and d is the separation of …

2010年8月23日 · Solve for the charge density given your original voltage (400 KV) and then substitute back into the electric field equation to find the actual fields. Of course though, for the specific question of the electric field strength at the ground it will be zero. But I have a feeling that there are a myriad of books that deal with the above problems.

2017年6月7日 · A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E⃗ at the point P, a distance d above the midpoint of the wire. What is the magnitude E of the electric field at point P? Throughout this part, express your answers in terms of the constant k, defined by k=1/4πϵ 0 ...

2021年11月12日 · Determine the direction and magnitude of the electric field at a point P lying a distance ##x>0## from the center of the disc along the axis of symmetry of the disc. Relevant Equations I know how to solve this problem. The electric field vector points in only one direction, so there is really only one integral to do.

2016年3月13日 · The beam is a form of electromagnetic raditation with both electric and magnetic field components. (a) Calculate the intensity of the beam in units of W/m^2 (b) Calculate the energy (delta U) delivered in a time of t = .065 s in Joules. (c) Use the intensity of the beam (I) to calculate the amplitude of the electric field in V/m

2017年12月6日 · Find the general formula for the x component of the electric field if the charge density p varies only with x throughout all space. Homework Equations The Attempt at a Solution I started using the poisson equation [tex]\bigtriangledown \bullet \bar{E} = \frac{p}{\varepsilon_{0}}[/tex]

2010年7月2日 · What is the direction of the electric field of a long line? The electric field of a long line is directed radially outward from the line, meaning it forms a cone shape with the line at its center. The direction of the field can be determined using the right hand rule, where the fingers point in the direction of the electric field and the thumb ...

2008年2月10日 · A long glass filament carries a charge density [tex]\lambda = - 2.7{\rm{ nC/m}}[/tex] . What is the magnitude of the electric field 0.67 mm from the filament? The Attempt at a Solution Did I do this problem correctly? I'm guessing not because my answer has an extra /m . Shouldn't it simply be N/C? [tex]

2012年8月18日 · Homework Statement A proton (+e) accelerates from rest in a uniform electric field of 640 N/C. At some later time, the proton's speed is 1.20 x 10^6 m/s. Find the acceleration of the proton. The mass of a proton is 1.67x10^-27 kg. Charge on a proton is +1.6x10^-19C. Homework Equations...

2012年10月25日 · Electric field caused by a charge (or group of charges) is defined in terms of its effect on a test charge, given by the formula: E ⃗=lim┬(q_(0→0) )⁡〖F ⃗/q_0 〗 I understand that the point charge must be infinitesimally small in order not to affect the field in question, so it makes sense to take the limit of q[itex]_{0}[/itex] to 0.