2015年4月5日 · For the bottom compound, we must compare two carbon groups, and the alkene containing one is higher priority. On the other side, nitro is higher priority than the carbon group. Again, the higher priority groups are trans, which means that the stereochemistry is E. In general, it is unnecessary to define the E/Z stereochemistry until the ring ...

2021年8月30日 · For either side you apply the CIP rules, and then, by the book, the double bond either is (E)-, or (Z)-configurated. If you are unsure how to trade with double bonds/cyclic substituents, see e.g. the answers here on chemistry.se) and then post your solution as self-answer. $\endgroup$ –

2019年7月16日 · (Z) is the same like cis (E) is the same like trans. BUT cis and trans is usually only for double bonds with 2 different substituents. Confusion can arise when, for instance, you have 2-halobut-2-enes, because some take the highest priority when determining if this is cis or trans whereas others may take the identical groups.

2022年2月18日 · Z precedes E for double bonds. For the molecules I asked the question about, we should select the in-cycle atom of one of the double bonds as a stereocenter. Then, while constructing the digraph, we will see that going one or the other way around the central ring formally makes the other quinone double bond either E or Z. Now let us look back ...

2021年5月10日 · The compound is a tetra-substituted alkene with four different groups. Thus, it could be a (E)- or (Z)-ethene. To find the priority of the groups, you must follow CIP rules. The four groups are cyclobut-1-enyl, cyclobut-2-enyl, 2-methylcyclobutyl, and 1-methylcyclobutyl.

2017年6月5日 · Now, after deciding the seniority groups on one carbon (i.e.on one side if the double bond) do the same for the other doubly bonded carbon. Now if the higher ranked groups are on same side of the double bond then the notation is "Z" otherwise it will be "E".

2017年3月13日 · Here, A has a greater atomic number than B, which has a greater atomic number than C. To assign E,Z designations you would divide the double bond into left and right portions and assign priorities. On the right side, A > C. However, on the left side, B = B.

2016年4月9日 · Does a GC analysis typically seperate E / Z isomers? I'm reading a paper that confirms that the product it synthesized was indeed the (E,E) isomer by coinjecting a standard sample on the GC. My question is, had they actually made an (Z,Z) or (E,Z) or (Z,E) would a typical GC show two different peaks?

2021年5月6日 · You get it correct half the time. Stereochemical descriptors like E and Z should be italicised, placed in parentheses, and connected to the main name by a hyphen: so the correct names are (E)-stilbene and (Z)-stilbene. $\endgroup$ –

2018年9月24日 · $\begingroup$ @user35715: The transformation of E- to Z-cyclooctene is a configurational change that involves bond breaking be it sigma or pi bonds. But this is not the issue. Think about the E-double bond of cyclooctene "jumping rope with the methylene chain", which interconverts enantiomers.