Derivatives of inverse trig functions sec^-1(x) and csc^-1(x)
I am studying for a final at the moment for AP Calc BC and could only fid proofs for deriving the inverses of trig functions sine, cosine, tangent, and cotangent. If possible, I would like to request a tutorial on proving the derivative of sec^-1(x) and csc^-1(x). Thank you!-Colby Cartier
Derivatives of sec (x) and csc (x) - Khan Academy
Let's explore the derivatives of sec(x) and csc(x) by expressing them as 1/cos(x) and 1/sin(x), respectively, and applying the quotient rule. We discover that the derivative of sec(x) can be written as sin(x)/cos²(x) or tan(x)sec(x), and the derivative of csc(x) can be expressed as -cos(x)/sin²(x) or -cot(x)csc(x).
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Learn how to find the derivatives of sec(x) and csc(x) with Khan Academy's step-by-step video tutorials.
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Review trigonometric ratios, including sine, cosine, and tangent, and their applications in right triangles.
tan (x), cot (x), sec (x) va csc (x) ning hosilalari (mashq qiling ...
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