Why is aluminium carbonate unstable? - Chemistry Stack Exchange
2018年6月13日 · Aluminum carbonate, if existed, would decompose by the following reaction: $$\ce{Al2(CO3)3 → Al2O3 + 3 CO2}$$ to $\ce{CO2}$ and $\ce{Al2O3}$, with a release of …
Does aluminium carbonate exist? - Chemistry Stack Exchange
2017年6月12日 · Al 2/3 O (s) + CO 2 (g) = Al 2/3 CO 3 (s) is about 10 GPa... Or you could make an Al 2 (CO3) 3 (aq) solution with concentration of $10^{-5}$ M. Well, still not impossible. And …
Consider the following chemical equation: Al2 (CO3)3 Al2O3
Al2(CO3)3 Al2O3+3CO2. If the reaction described by this chemical equation started with 4.79 grams of Al2(CO3)3 and resulted in 2.44 grams of CO2, what is the percent yield of CO2? The …
Solved 2 Al (NO3)3 + 3 Na2CO3---> Al2 (CO3)3 + 6 NaNO3Which …
Question: 2 Al(NO3)3 + 3 Na2CO3---> Al2(CO3)3 + 6 NaNO3Which product is precipitate?a)IF 0.400 moles of aluminum nitrate is reacted with 0.700 moles ofsodium carbonate, now many …
Solved How many atoms of oxygen are contained in 47.6 g - Chegg
The molar mass of Al2(CO3)3 is 233.99 g/mol. (Points : 1) 3.68 × 1023 O atoms 1.23 × 1023 O atoms 1.10 × 1024 O atoms 2.96 × 1024 O atoms 2.87 × 1025 O atoms Your solution’s ready …
Solved For 5 points, identify the number of molecules in - Chegg
None of the above For 5 points, identify the number of grams in 3.51 moles of Al2(CO3)3. Select one: O a. 821 ob. 0.0403 O c. 2.11 x 1024 O d. 152 e. None of the above For 5 points, identify …
Solved The molality of an Al2 (CO3)3 solution is 3.8 m. What - Chegg
Find the molecular weight of the solute. unit: A 114 mg sample of a non-electrolyte isolated from throat lozenges was dissolved in enough water to make 14.0 mL of solution at 21.3°C. The …
Solved How many atoms of carbon are contained in 47.6 g - Chegg
The molar mass of Al2(CO3)3 is 233.99 g/mol. Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
Solved 3) Aluminum chloride and sodium carbonate react - Chegg
Question: 3) Aluminum chloride and sodium carbonate react according to the equation: AlCl3 + Na2CO3 → Al2(CO3)3 + NaCl What coefficient must be placed in front of the NaCl to balance …
Answered: 2AlCl3 + 3Na2CO3 ---> Al2(CO3)3 - bartleby
2AlCl3 + 3Na2CO3 ---> Al2(CO3)3 + 6NaCl If you have 15 grams of aluminum chloride and 15 grams of sodium carbonate, which reactant is the Limiting reactant?