2016年3月12日 · How do you solve for x in #ax+b=0#? Algebra Linear Equations Formulas for Problem Solving. 1 Answer Tony B ...

2018年3月27日 · First of all, the root would be x=-a. Treat the equation as if it is a full quadratic, and then attempt to solve when bne0 as well as when b=0 to prove it. Let's write out the quadratic formula first: x=(-b+-sqrt(b^2-4ac))/(2a) This assumes the equation looks like: ax^2+bx+c in this scenario: a=1 b=a c=b Filling out the equation: x=(-a+-sqrt(a^2-4b))/(2) Now, if bne0, the …

2024年1月1日 · If ax + b = 0, is x 0 ? (1) a + b 0 (2) a - b 0. awesome explanations both bunuel and mainhoon --these two approaches would probably serve two different types of students really well. nice work!

2025年2月20日 · I was mistakenly did so with this Q and from (1)+(3); I got both a>0 (combine LHS) and b>0 (Subtract LHS), which results in X<0, if ax + b = 0, corresponding to ans. C Please correct me on this point so that next time I can apply only the combination of LHS and not subtraction in context of equation with same sign. Thank you!

In this question with quadratic equation of the form x^2+ax+b=0, the roots are also a & b Hence, product of roots=b/1 a x b = b Hence a = 1 Sum of roots = -a a+b = -a b=-2a We know a =1 Hence b = -2 Hence option C

2018年1月24日 · See the explanation below The quadratic equation is ax^2-(a+b)x+b=0 In order for this quadratic equation to have solutions, the discriminant >=0 The discriminant is ...

2018年1月12日 · Proved. Let The roots of the equation x^2 + ax + b = 0 be alpha and beta. Similarly, Let the roots of the equation x^2 + bx + a = 0 be alpha and gamma. [There is a common root.] So, alpha + beta = -a rArr alpha = -(a + beta) And alpha + gamma = -b rArr alpha = -(b + gamma) So, -(a + beta) = -(b + gamma) rArr a + beta = b + gamma rArr beta - gamma = b -a …

2018年6月28日 · Please refer to a Proof in the Explanation. Since, the eqn. x^2+ax+b=0 has equal roots, its discriminant must be zero. :. a^2-4b=0, or, b=a^2/4.....(star). Hence, the eqn. becomes, x^2+ax+a^2/4=0. :. (x+a/2)^2=0 , or, x=-a/2. …

2018年6月23日 · We know that," If , # l and m# are the roots of #Ax^2+Bx+C=0#,then #(i)# the SUM of the Roots #=l+m=-B/A# #(ii)# the PRODUCT of the Roots #=l*m=C/A#

2018年6月3日 · We know that, #"If"# #alpha and beta# #"are the roots of the quadratic equation :"# #color(red)(Px^2+Qx+R=0,then,alpha+beta=-Q/Pand alpha*beta=R/P#