2018年5月3日 · How do you use the binomial series to expand #1 / (1+x)^4#? How do you use the binomial series to expand #f(x)=(1+x)^(1/3 )#? See all questions in The Binomial Theorem

2018年6月27日 · Notice that in our sequence is 0-99.4=-99.4 -99.4-99.4=0 -198.8-99.4=99.4... So we are dealing with an arithmetic sequence with difference -99.4. Each term is build up "adding" -99.4 to prior term. So the recursive formula is f(n)=f(n-1)+(-99.4)

2014年9月19日 · Let us find a fraction for #0.121212...# by splitting it into #=0.12+0.0012+0.000012+cdots# by rewriting each term as a fraction,

2018年7月28日 · See proof below 1=1\\mod 5 1^{99}=1^99\\mod 5 1^{99}=1\\mod 5 Similarly, 2^{99}=2^{99}\\mod 5 3^{99}=(-2)^99\\mod 5 4^{99}=(-1)^99\\mod 5 5^{99}=0\\mod 5 \\therefore ...

2017年12月3日 · What is the z value for a 90, 95, and 99 percent confidence interval? Statistics Inference with the z and t Distributions z Confidence intervals for the Mean 1 Answer

2014年3月21日 · The acceptability of a percent error depends on the application. > In some cases, the measurement may be so difficult that a 10 % error or even higher may be acceptable.

2018年3月7日 · 55 Add the first and the last numbers of the sequence and repeat for the other sets of numbers. 1 + 10 = 11 2 + 9 = 11 3 + 8 = 11 4 +7 = 11 5 + 6 = 11 This gives 5 sets of numbers that equal 11. 5 xx 11 = 55

2016年3月4日 · 2.576 Z score of a 99 confidence interval is 2.576. The third quartile, denoted #Q_3#, is the data value such that what percent of the values are below it?

A sample of rock is known to be #4.2xx10^(9)# years old. It contains 1.235 g of U 238. What is the mass of Pb 206 present in the sample assuming all of it originated from the decay of U 238 which has a half life of #4.489xx10^9# years ?

2017年8月23日 · What is 1 + 2 + 3 + ..... + 99 + 100 equal to? Precalculus. 1 Answer