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\[x-6=9\] +. > < ...

Apr 17, 2016 · How do you solve #6^x + 4^x = 9^x#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic ...

Dec 8, 2016 · Exponent Form: 6^5 We are given five 6's, so we simply start out with the number that is being multiplied over and over again. Which in this case, is 6. 6*6*6*6*6=7776 To make things easier though, we write repetitive numerals in exponent form. You will still get the same answer either way. 6^5=7776 Answer: 6^5

May 20, 2018 · What are the units used for the ideal gas law?

#x^3 -x^2-5x+5# can be factored over the integers as #(x-1)(x^2-5)# #x^2-5# cannot be factored using integer coefficients. (It is irreducible over the integers.) over the real numbers #x^2-5 = (x-sqrt5)(x+sqrt5)# One more: #x^2+1# cannot be factored over the real numbers, but over the complex numbers it factors as #x^2+1=(x-sqrt(-1))(x+sqr(-1))#

You can put this solution on YOUR website! Log(base 9)(x-6)+log (base 9)(x-6)=1 log9[(x-6)(x-6)]=log9(9) x^2-12x+36=9

Jul 22, 2015 · =color(blue)((-6x-9)/(x-6) (-6x)/(x-6) - 9/(x-6) Since the denominators of both the terms are equal we can simply add the numerators: =color(blue)((-6x-9)/(x-6)

Sep 27, 2015 · How do you show whether the improper integral #int (x^2)/(9+x^6) dx# converges or diverges from negative infinity to infinity? Calculus Tests of Convergence / Divergence Integral Test for Convergence of an Infinite Series

Mar 18, 2016 · I would integrate by trigonometric substitution, then check that the limit exists. We can take out a constant factor, so int_-oo^oo (79x^2/(9 + x^6)) dx converges if and only if int_-oo^oo (x^2/(9 + x^6)) dx converges. int (x^2/(9 + x^6)) dx = 1/9tan^-1(x^3/3) As xrarroo, we have tan^-1(x^3/3) rarr pi/2 (and as xrarr-oo, we have tan^-1(x^3/3) rarr -pi/2) so both int_-oo^0 …