The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive …

Nov 10, 2016 · Solving and keeping the equation balanced gives: 6x −4 = 20 6x −4 +4 = 20+ 4 6x −0 = 24 6x = 24 6 ⋅ x 6 = 24 6 (6 6) ⋅ x = 4 1 ⋅ x = 4 x = 4

Oct 10, 2016 · -6x-24 Distribute the -6 throughout the set of parenthesis. Meaning, multiply -6 to each term within the parenthesis. -6xxx = -6x and -6xx4 = -24 -6x-24

Apr 17, 2016 · x= (ln ( (1+sqrt (5))/2))/ (ln (3/2)) Divide by 4^x to form a quadratic in (3/2)^x.

Sep 4, 2016 · We have: 6x − 4 = 3x + 2 Let's subtract 3x from both sides of the equation: ⇒ 3x − 4 = 2 Then, let's add 4 to both sides: ⇒ 3x = 6 Finally, to solve for x, let's divide both sides by 3: …

Apr 17, 2019 · How do I formally show the radius of convergence of the Taylor series of f(x) = x 6 − x 4 + 2 at a = − 2?

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Jul 16, 2018 · 7 − 3(x −4)1 +5(x − 4)2 If you had been asked to find the approximation of f (x) at x = 4.3, you could now just plug in x = 4.3 into this, giving the approximation:

Oct 19, 2015 · Can anyone tell me how to solve this? $x^6-x^5+x^4-x^3+x^2-x+1=0$ What I got to was $x^7+1=0$. Thanks in advance.

You can simplify polynomials only if they have roots. You can think of polynomials as numbers, and of monomials of the form (x-a) as prime numbers. So, as you can write a composite …