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x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

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Rewrite 4x^{2}-1 as \left(2x\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

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Check that the middle term is two times the product of the numbers being squared in the first term and third term. 4x = 2⋅(2x)⋅1 4 x = 2 ⋅ (2 x) ⋅ 1. Rewrite the polynomial. (2x)2 − 2⋅(2x)⋅1+12 (2 x) 2 - 2 ⋅ (2 x) ⋅ 1 + 1 2.

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Mar 30, 2022 · Our Website: https://linktr.ee/mathstoon In this video, we will learn how to factorize 4x^2-1. 4x^2-1 = (2x)^2-1^2 = (2x-1) (2x+1) Subscribe for more videos and stay tuned!...

4x^{2}-4x+1=4\times \frac{2x-1}{2}\left(x-\frac{1}{2}\right) Subtract \frac{1}{2} from x by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.