2016年3月14日 · #sqrt(32x^3# #=sqrt (32 * color(purple) ( x^2) * x^1# Simplifying #sqrt32#; #sqrt(32) = sqrt(2*2*2*2*2) = sqrt(color(blue)(2^2 * 2^2) * 2)=color(blue)( 2 *2) sqrt2 ...

2016年2月7日 · the given : #32x^3-4# common monomial factor #=4# factor out #4# first #4(8x^3-1)# use the "difference of two cubes " form. #a^3-b^3=(a-b)(a^2+ab+b^2)# for #8x^3-1# so that #8x^3-1=(2x-1)(4x^2+2x+1)# final answer #32x^3-4=4*(2x-1)(4x^2+2x+1)#

2018年7月4日 · color(blue)(x=8) 2^(x-3)=32 Notice: 32=2^5 Therefore: 2^(x-3)=2^5 Since both bases are equal, then both exponents are equal: :. x-3=5 x=8

#{: ("both terms are positive","or","both terms are negative"), (x>(3+sqrt(137))/2,,x < (3-sqrt(137))/2) :}# If you like you could use a calculator to evaluate these irrational expressions: #x > 7.352349955color(white)("XX")orcolor(white)("XX")x < -4.35234995# We could verify that these results are reasonable by examining the graph of #x^2-3x ...

2016年5月16日 · How do you simplify #32^(3/5)#? Algebra Exponents and Exponential Functions Fractional Exponents. 1 Answer

2016年8月22日 · f(x) has zeros 1, -1/8 and 3/4 >f(x) = 32x^3-52x^2+17x+3 By the rational roots theorem, any rational zeros of f(x) are expressible in the form p/q for integers p, q with p a divisor of the constant term 3 and q a divisor of the coefficient 32 of the leading term.

2016年10月29日 · #3/5# th of the cost is #13.32#. When "translating" words to an equation, "of" means multiplication and "is" means equal. Let #x=# the cost. #3/5 x = 13.32# Multiply both sides by #5/3# #5/3 * 3/5 x = 5/3 * 13.32# #cancel5/cancel3 * cancel3/cancel5 x = (5*13.32)/3# #x=22.2#, so the cost of the present is #$22.20#.

2016年11月1日 · x = 11/2 = 5 1/2 = 5.5 When you have a variable in the index, you are working with an exponential equation. There are 2 types of exponential equations those that can be calculated by using known powers, and those that need to be calculated using logs and a calculator. This example is an example of the former, because both bases are powers of 2. …

2017年6月20日 · -8 (-32)^(3/5) = ((-2)^5)^(3/5) = (-2)^(5*3/5) = (-2)^3 = =-8. 8088 views around the world ...

2016年1月10日 · -32/x^2 Before differentiating this function it requires to be written in the form ax^n note that the derivative of a function must be in the correct form before you can differentiate it. f(x) = ax^n rArr f'(x) =nax^(n - 1 ) 32/x = 32x^-1 now differentiating gives -1xx32x^-2 rewriting with a positive index the gives -32/x^2