
How do you simplify (x^3)^2? - Socratic
2018年7月2日 · x^6 >"using the "color(blue)"law of exponents" •color(white)(x)a^mxxa^n=a^((m+n)) (x^3)^2=x^3xxx^3=x^((3+3))=x^6
What is 3 -3 x 6 + 2? - Socratic
2016年7月9日 · -13 Using the mnemonic Please Excuse My Dear Aunt Sally we are reminded that in the order of operations we follow P = Parenthesis larr brackets E = Exponents M …
Find the solutions of x^2=2^x? - Socratic
2016年11月12日 · x_1 = -0.7667 to 4dp x_2= 2 x_3 = 4 > x^2 = 2^x There is no "easy" way to solve this equation. First let us look at the graphs: We can see there is one solution in the …
Factorise? a) x^4+2x^3+3x^2+2x+1 - Socratic
x^4+2x^3+3x^2+2x+1=(x^2+x+1)^2. When you have a "symmetric polynomial", one where the coefficients are the same when you read them forwards and backwards, like …
How do you do you multiply a 3x2 matrix by a 2x2 matrix?
2015年10月22日 · Here is an example (rather than a formula, it is a process). Here is an example ((4, 5),(3, 4),(1,2)) ((3, 1),(0, 3)) Find the first row of the product Take the first row of ((4, 5),(3, …
How do you find the derivative of 3/x^2? - Socratic
2016年2月25日 · How do you find the derivative of #3/x^2#? Calculus Basic Differentiation Rules Power Rule. 1 Answer Jim G
How do you simplify x/x^3? - Socratic
2015年7月9日 · 1/x^2 There is a rule when it comes to dividing exponents that have the same base; here, we have the common base of x. The rule is: x^a/x^b=x^(a-b) The question is to …
How do you integrate int x^3 / sqrt[1-x^2] using trigonometric ...
2018年3月13日 · int x^3/sqrt(1-x^2) dx = -sqrt(1-x^2) ((x^2 + 2)/3) +C Substitute x=sint, dx=costdt. As the integrand is defined only for x in (-1,1) then t will vary accordingly in (-pi/2,pi/2) and we …
What is # 3^(3/2)# in radical form? - Socratic
2018年4月10日 · The answer is sqrt(3^3), or to simplify it even further, sqrt27. Say we have a whole number c, raised to the power of a fraction n over d, with n being the numerator and d …
How do you expand the binomial (x-2)^3? - Socratic
2016年10月16日 · (x-2)^3 =x^3-6x^2+12x-8 (x-2)^3 =x^3+(""_1^3)x^2(-2)+(""_2^3)x(-2)^2+(-2^3) (""_1^3)=(3*2*1)/2=3 (""_2^3)=(3*2*1)/2=3 You can also use Pascal's triangle So the answer ...