x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

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2x-3x=9 One solution was found : x = -9 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

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May 2, 2018 · To do so, first subtract 3 from both sides of the equation: 2x = 6. Hope this helps! x = 3 2x + 3 = 9 We want to find the variable x, so we have to make it alone.

Jan 31, 2020 · The solution to the equation 2x + 3 = 9 is found by isolating x through subtraction and division, resulting in x = 3. This solution can be verified by substituting it back into the …