2015年11月24日 · 33097 views around the world You can reuse this answer ...

2003年7月13日 · That leaves you with (2n+2)(2n+1)n!n! on top now, and (n+1)!(n+1)! on the bottom. so convert each (n+1)!= (n+1)n! -- there it is, the n!, and done twice as well to cancel the top n!'s And so there's your (2n+2)(2n+1) / (n+1)(n+1) * always remember to rewrite the largest factorial term so that it will eventually correspond to a smaller term.

2017年12月9日 · I assume you are referring to 2n^2 electrons per energy level... Refer to this answer for info on quantum numbers. Well, for a given n, we have the following properties: l_max = n-1 2l+1 orbitals per subshell From this, we find that for a given energy level n, there exist sum_(l=0)^(n-1)(2l+1) = (2(0) + 1) + (2(1) + 1) + . . . + (2l_max + 1) orbitals in the energy level. …

2015年9月15日 · 2n 2 would be the most likely because the exponent operation takes precedence over the multiplication (you'd square n before multiplying by 2), so that's 2 · n · n (2n) 2 would be spoken as "2 n quantity squared" where the quantity implies that 2n is in parentheses.

2017年2月8日 · How do you simplify the factorial expression #((2n-1)!)/((2n+1)!)#? Precalculus The Binomial Theorem Factorial Identities. 1 Answer

2015年12月24日 · A useful idea in this context is "the degree of unsaturation", which I will outline with the answer. "Alkanes:" C_nH_(2n+2); "Alkene:" C_nH_(2n); "Alkyne:" C_nH_(2n-2); "Alkyl residue:" C_nH_(2n+1); "Aldehyde/ketone:" C_nH_(2n)O; "Cycloalkane:" C_nH_(2n) A fully saturated hydrocarbon, an alkane, has general formula C_nH_(2n+2): n =1, methane; n =2, …

2015年12月10日 · There are other ways of writing it, however none of them are simplifications. While there isn't a simplification of ((2n)!)/(n!), there are other ways of expressing it.

2015年5月11日 · what is the first five terms of the sequence an=2n^2. Guest May 11, 2015. 0 users composing answers..

2015年5月17日 · 2n^2 + 5n + 2 = 2n^2 + 4n + n + 2 = 2n(n+2)+1(n+2) = (2n+1)(n+2) The 'trick' is the particular separation of 5n into 4n+n, which results in the ratio of the first to second coefficients being the same as the ratio of the third to fourth coefficients.

2017年7月15日 · The #n#th term of a sequence is #2n^2#. What is the 4th term of the sequence? Precalculus. 1 Answer